The Question is Incomplete The complete question with figure is below.
Answer:
Therefore the equation to solve for b is
![\tan 30 = \dfrac{5}{b}](https://tex.z-dn.net/?f=%5Ctan%2030%20%3D%20%5Cdfrac%7B5%7D%7Bb%7D)
Step-by-step explanation:
Given:
In Right Angle Triangle ABC
∠C = 90°
BC = 5 cm
AB = 10 cm
∠A = 30°
To Find:
b = ?
Solution:
In Right Angle Triangle ABC Tangent identity we have
![\tan A = \dfrac{\textrm{side opposite to angle A}}{\textrm{side adjacent to angle A}}](https://tex.z-dn.net/?f=%5Ctan%20A%20%3D%20%5Cdfrac%7B%5Ctextrm%7Bside%20opposite%20to%20angle%20A%7D%7D%7B%5Ctextrm%7Bside%20adjacent%20to%20angle%20A%7D%7D)
Substituting the values we get
![\tan 30 = \dfrac{BC}{AC}\\\\\tan 30 = \dfrac{5}{b}](https://tex.z-dn.net/?f=%5Ctan%2030%20%3D%20%5Cdfrac%7BBC%7D%7BAC%7D%5C%5C%5C%5C%5Ctan%2030%20%3D%20%5Cdfrac%7B5%7D%7Bb%7D)
Therefore the equation to solve for b is
![\tan 30 = \dfrac{5}{b}](https://tex.z-dn.net/?f=%5Ctan%2030%20%3D%20%5Cdfrac%7B5%7D%7Bb%7D)
Answer:
f(x) = -3|x| + 2x - 1
f(-5) = -3|-5| + 2*(-5) - 1
= -3*5 + 2*(-5) - 1
= -15 - 10 - 1
= -26
Hope this helps!
:)
2/5*1/2=2/10
his neighbor will get 2/10quart or 0.2quarts of jelly
Answer:
The expression that represents the number of days until only 10% remains is T((d) 10 %) =100×
.
Step-by-step explanation:
The equation for half life is of the form
A = A₀×
.........................................................................(1)
Where
A = Final amount
A₀ = Initial amount
t = Time
h = Half life
For the equation T(d) = 100×2⁽⁻²⁾....................................(2)
We have by comparison with the equation for half life
2 ≡
and and the equation (2) can be written as
Percentage remaining after 2 half lives is
×100=100×![(\frac{1}{2} )^{2 }](https://tex.z-dn.net/?f=%28%5Cfrac%7B1%7D%7B2%7D%20%29%5E%7B2%20%7D)
However if the half life of Technetium-99m is 6 hours then we have for one day
×100=100×
Therefore an expression that represents the number of days until only 10% remains is
×100=100×
= 10 %
=![\frac{1}{10}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B10%7D)
= ㏑
= ㏑(
)
=
×㏑
= ㏑(
)
=
= 3.322
Therefore the expression for the number of days 10 % of Technetium-99m will be remaining is
T((d) 10 %) =100×![(\frac{1}{2} )^{3.322}](https://tex.z-dn.net/?f=%28%5Cfrac%7B1%7D%7B2%7D%20%29%5E%7B3.322%7D)