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2 years ago

The image shows a quadrilateral inscribed in a circle. Select ALL true statements.

Mathematics

1 answer:

dimulka [17.4K]2 years ago

4 0

Answer:

c, d, e, g

Step-by-step explanation:

c. you already got it correct

d. since angle b is 100, arc AC must be two times that amount, which is 200

e. opposite angles of a quadrilateral are supplementary (adds up to 180). to find CDA, you have to do 180 minus 100 (which is the measure of angle B) to get 80

g. opposite angles of a quadrilateral are supplementary (adds up to 180). to find BCD, you need to do 180 minus 70 (which is the measure of angle A) to get 110

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Advertising expenses are a significant component of the cost of goods sold. Listed below is a frequency distribution showing the

Alexxandr [17]

Answer:

Step-by-step explanation:

The table can be computed as:

Advertising Expenses ($ million) Number of companies

25 up to 35 4

35 up to 45 19

45 up to 55 27

55 up to 65 16

65 up to 75 9

TOTAL 75

Let's find the probabilities first:

$P(25 - 35) = P \Big(\dfrac{25-50.93}{10.80}$

For 35 up to 45

$P(35 - 45) = P \Big(\dfrac{35-50.93}{10.80}$

For 45 up to 55

$P(45 - 55) = P \Big(\dfrac{45-50.93}{10.80}$

For 55 up to 65

$P(55 - 65) = P \Big(\dfrac{55-50.93}{10.80}$

For 65 up to 75

$P(65 - 75) = P \Big(\dfrac{65-50.93}{10.80}$

Chi-Square Table can be computed as follows:

Expense No of Probabilities(P) Expe $(O-E)^2$ $\dfrac{(O-E)^2}{E}$

compa cted E (n*p)

nies (O)

25-35 4 0.0612 75*0.0612 = 4.59 0.3481 0.0758

35-45 19 0.2218 75*0.2218 = 16.635 5.5932 0.3362

45-55 27 0.3568 75*0.3568 = 26.76 0.0576 0.021

55-65 16 0.2552 75*0.2552 = 19.14 9.8596 0.5151

65-75 9 0.0839 75*0.0839 = 6.2925 7.331 1.1650

$\sum \dfrac{(O-E)^2}{E}= 2.0492$

Using the Chi-square formula:

$X^2 = \dfrac{(O-E)^2}{E} \\ \\ Chi-square \ X^2 = 2.0942$

Null hypothesis:

$H_o: \text{The population of advertising expenses follows a normal distribution}$

Alternative hypothesis:

$H_a: \text{The population of advertising expenses does not follows a normal distribution}$

Assume that:

$\alpha = 0.02$

degree of freedom:

= n-1

= 5 -1

= 4

Critical value from $X^2 = 11.667$

Decision rule: To reject $H_o \ if \ X^2$ test statistics is greater than $X^2$ tabulated.

Conclusion: Since $X^2 = 2.0942$ is less than critical value 11.667. Then we fail to reject $H_o$

6 0

3 years ago

Answerrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrr

Ulleksa [173]

Answer:

5x²-2x+7+2x²+6x-9
5x²+2x²-2x+6x+7-9
7x²+4x-2

so, 7x²+4x-2 is yr answer.

hope it helps.

<h3>stay safe healthy and happy.</h3>

8 0

2 years ago

I need help with this problem. <br>

Zina [86]

Answer:

(1,4)

Step-by-step explanation:

Let's this of $y=\sqrt{x}$ which is it's parent function.

How do we get to $y=-\sqrt{x-1}+4$ from there?

It has been reflected about the a-axis because of the - in front of the square root.

It has been shifted right 1 unit because of the -(1) in the square root.

It has been moved up 4 units because of the +4 outside the square root.

In general:

$y=a(x-h)^2+k$ has the following transformations from the parent:

Moved right h units if h is positive.

Moved left h units if h is negative.

Moved up k units if k is positive.

Moved down k units if k is negative.

If $a$ is positive, it has not been reflected.

If $a$ is negative, it has been reflected about the x-axis.

$a$ also tells us about the stretching factor.

The parent function has a starting point at (0,0). Where does this point move on the new graph?

It new graphed was the parent function but reflected over x-axis and shifted right 1 unit and moved up 4 units.

So the new starting point is (0+1,0+4)=(1,4).

6 0

3 years ago

Read 2 more answers

Can someone help me with 9,10,11 ?

sergij07 [2.7K]

I could be wrong but i graphed it out and 9 is C , 10 is A , and 11 is C Hopefully it's right

3 0

3 years ago

Oliver draws a line on his paper and from a point on the line draws a circle. He then measures the radius of his circle and cons

olasank [31]

Dye answer is The letter D

7 0

3 years ago