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IgorLugansk [536]

2 years ago

14

RAMP 21.7 ft 8.5 ft 12 ft 20 ft 1. What is the total surface area of the ramp?

2 answers:

krok68 [10]2 years ago

4 0

Answer:

772.4 ft^2

Step-by-step explanation: pls mark brainliest :)

castortr0y [4]2 years ago

3 0

Answer:

772.4 ft^2

Step-by-step explanation:

find the area of each face. first the slanted rectangle. the dimensions of the slanted rectangle are 21.7ft by 12ft. so the area is 21.7*12=260.4ft^2. for the two triangles on the sides, each on has an area of 20*8.5/2=85. next for the smaller rectangle, the dimensions are 12ft by 8.5ft giving us an area of 102 ft^2. lastly for the base, it has dimensions of 20ft by 12ft giving us an area of 240ft^2. now you just add up all the areas: 260.4+85+85+102+240=772.4 (you might want to check my addition just in case)

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uysha [10]

Answer:

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5. (0, 1)

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Step-by-step explanation:

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3 0

3 years ago

Read 2 more answers

The square of a number is 15 more than 2 times the number

UkoKoshka [18]

x^2 = 2x + 15

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Factor:

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3 0

3 years ago

Of the students in Ms.Danver's class, 6 walk to school.This represents 30% of her students.How many Students are in Ms.Damver's

Kisachek [45]

There is 20 students. To find the answer you need to use porportionals and cross multiply.

6 0

3 years ago

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(1.)Find the slope of the line that passes through the given pair of points. (If an answer is undefined, enter UNDEFINED.) (?a +

jekas [21]

Answer:

1. The slope of the line is $m=\frac{-2b+3}{2a}$ .

2. The value of a is 18.

Step-by-step explanation:

If a line passes through two points, then the slope of the line is

$m=\frac{y_2-y_1}{x_2-x_1}$

(1)

It is given that the line passes through the points (-a + 3, b - 3) and (a + 3, -b). So, the slope of the line is

$m=\frac{-b-(b-3)}{a+3-(-a+3)}$

$m=\frac{-b-b+3}{a+3+a-3)}$

$m=\frac{-2b+3}{2a}$

The slope of the line is $m=\frac{-2b+3}{2a}$ .

(2)

If the line passing through the points (a, 1) and (6, 5), then the slope of the line is

$m_1=\frac{5-1}{6-a}=\frac{4}{6-a}$

If the line passing through the points (2, 7) and (a + 2, 1), then the slope of the line is

$m_2=\frac{1-7}{a+2-2}=\frac{-6}{a}$

The slopes of two parallel lines are same.

$m_1=m_2$

$\frac{4}{6-a}=\frac{-6}{a}$

On cross multiplication we get

$4a=-6(6-a)$

$4a=-36+6a$

$4a-6a=-36$

$-2a=-36$

Divide both sides by -2.

$a=18$

Therefore the value of a is 18.

8 0

3 years ago

6(-3r)=-39+3r what is the answer and work

masha68 [24]

<span>6(-3r)=-39+3r
-18r = -39+3r
39 = 18r + 3r
39 = 21r
39/21 = r
13/7 = r
r = 13/7</span>

8 0

3 years ago