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2 years ago

Pls help giving brainliest !!!!!!!!!!!

Biology

2 answers:

soldier1979 [14.2K]2 years ago

7 0

Answer:

Your answer is 2.

Explanation:

To calculate the mechanical advantage of a pulley you simply have to count the number of rope sections that support whatever object you are lifting (not counting the rope that is attached to the effort). For example, in a one pulley system the MA is 1. In a two pulley system the MA is 2.

Andrej [43]2 years ago

6 0

I’m just answering so the other person can get brainliest

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What is the importance of microtubles in cell division

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Which of the following statements about the functional consequences of single base-pair mutations are TRUE? Select the three cor

Alchen [17]

Answer:

these statements are true

B) Insertions or deletions of single base-pairs within a protein coding sequence probably change the amino acid sequence

D) Missense mutations always change the amino acid sequence encoded by a gene

E) Nucleotide substitutions outside of the coding sequence can affect the expression of a gene.

Explanation:

B) insertion or deletion of nucleotide in coding region of DNA can change the amino acid sequence encoded.

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2 years ago

What is the magnitude of the force exerted by the biceps fbiceps? What is the magnitude of the force exerted by the elbow felbow

Slav-nsk [51]

Answer:

The magnitude of the force exerted by the biceps $f_b_i_c_e_p_s$ is 218.38N

The magnitude of the force exerted by the elbow $f_e_l_b_o_w$ is 194.37N

Explanation:

Firstly , lets calculate the magnitude of force exerted by biceps $f_b_i_c_e_p_s$ -

Mass of the forearm=

$m_f=1.50kg$

Mass of the ball =

$m_b_a_l_l=950g$

= 0.950kg

so, weight of the forearm=

$w_f=m_f$ g

weight of the ball=

$w_b_a_l_l=m_b_a_l_l$ g

Now , balancing torque about the elbow , we have-

$F_b_i_c_e_p_s\times d_b_i_c_e_p_s= w_f\times\frac{d_b_a_l_l}{2} + w_b_a_l_l\times d_b_a_l_l$

(here , distance of the bicep is 2.50cm = 0.025m and distance of the ball is 36cm= 0.36m)

Now putting the given values in the formula -

$F_b_i_c_e_p_s\times 0.025= 0.95\times9.8\times\frac{0.36}{2} +1.50\times 0.36$

$F_b_i_c_e_p_s=218.38N$

Now, lets calculate the force exerted by elbow $F_e_l_b_o_w$ -

Balancing the vertical forces

$F_b_i_c_e_p_s=F_e_l_b_o_w+w_f+w_b_a_l_l$

$F_e_l_b_o_w = 218.38-(1.00\times9.8)-(0.95\times9.8)$

$F_e_l_b_o_w=194.37N$

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2 years ago

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