Answer:
The image is sideways.
But if your graph is like on the image, then the answer is: {y│-3 ≤ y ≤ 4}
Range is the set of y values
Least function value is -3 and greatest is 4
-- The graph looks like a line that passes through the origin,
and slopes up to the right at a 45-degree angle.
-- Point #1 on the line:
. . . . . Pick any number.
. . . . . Write it down twice.
. . . . . Call the first one 'x'. Call the second one 'y'.
-- Point #2 on the line:
. . . . . Pick any other number.
. . . . . Write it down twice.
. . . . . Call the first one 'x'. Call the second one 'y'.
-- Point #3 on the line:
. . . . . Pick any other number.
. . . . . Write it down twice.
. . . . . Call the first one 'x'. Call the second one 'y'.
Rinse and repeat, as many times as you like,
until the novelty wears off and you lose interest.
Well, I'm not completely sure, because I don't know the formal definition
of "corner" in this work. It may not be how I picture a 'corner'.
Here's what I can tell you about the choices:
A). (0, 8)
This is definitely a corner of the feasible region.
It's the point where the first and third constraints cross.
So it's not the answer.
B). (3.5, 0)
This is ON the boundary line between the feasible and non-feasible
regions. But it's not a point where two of the constraints cross, so
to me, it's not what I would call a 'corner'.
C). (8, 0)
Definitely not a corner, no matter how you define a 'corner'.
This point is deep inside the non-feasible zone, and it doesn't
touch any point in the feasible zone.
So tome, this looks like probably the best answer.
D). (5, 3)
This is definitely a corner. It's the point of intersection (the solution)
of the two equations that are the first two constraints.
The feasible region is a triangle.
The three vertices of the triangle are (0,8) (choice-A),
(0,-7) (not a choice), and (5,3) (choice-D) .
region is a triangle
Answer:
13/24 is your answer for this
Step-by-step explanation:
Answer: Probability that 3 are consonants and 2 are vowels is 0.3996.
Step-by-step explanation:
Since we have given that
Number of unique consonant tiles = 10
Number of unique vowel tiles = 5
Total number of tiles = 10+5=15
we need to pick 5 tiles randomly,
So, Probability that 3 are consonants and 2 are vowels is given by
Hence, Probability that 3 are consonants and 2 are vowels is 0.3996.