$\frac{ {x}^{2} - 7x + 12}{ {x}^{2} - x - 12 } \\ = \frac{ {x}^{2} - 4x - 3x + 12 }{ {x}^{2} - 4x + 3x - 12 } \\ = \frac{x(x - 4) - 3(x - 4)}{x(x - 4) + 3(x - 4)} \\ = \frac{(x - 3)(x - 4)}{(x + 3)(x - 4)} \\ = \frac{x - 3}{x + 3}$

x² - x - 12 ≠ 0

x² - 4x + 3x - 12 ≠ 0

x (x - 4) + 3 (x - 4) ≠ 0

(x + 3)(x - 4) ≠ 0

x ≠ -3 or x ≠ 4

(B)

3 0

3 years ago

Equation B: 3x+2x+6=6x-5 ( does that have one solution, no solution, or many solutions?) and explain why

Hoochie [10]

It has one solution.

please see the attached picture for full solution

Hope it helps

Good luck on your assignment...

7 0

3 years ago

Read 2 more answers

At Keller's Bike Rentals, it costs 42$ to rent a bike for 8 hours. How many hours of bike use does a customer get per dollar? ro

Verizon [17]

Answer:336

Step-by-step explanation:

5 0

3 years ago