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Svetllana [295]
3 years ago
8

A car has 15 gallons of gas in its tank. The car travels 35 miles per gallon of gas. It uses 135 of a gallon of gas to go 1 mile

. How much gas does it use to go 100 miles?
Mathematics
2 answers:
timama [110]3 years ago
6 0

2.86 gallons

Step-by-step explanation:

If 1/35 gallon of gas = 1 mile

To travel 100 miles,

1/35 * 100

= 0.0286 * 100

= 2.86 gallons

Therefore, the car needs 2.86 gallons of gas to travel 100 miles

Ahat [919]3 years ago
3 0
2.86 gallons is the answer
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I hope this is right i think the answer is 40

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Can you help me with number 6? <br> Confused abit <br> Please
Sunny_sXe [5.5K]

You can see the three diagram attached. Each link is labeled with the probability: you have probability 1/6 that a six is rolled, and 5/6 that it is not rolled.


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First question:

To get three sixes, you have to choose the left path at each roll. The probability is always 1/6, so the answer is


\frac{1}{6} \times \frac{1}{6} \times \frac{1}{6} = \frac{1}{6^3}


Second question:

To get no sixes, you have to choose the right path at each roll. The probability is always 5/6, so the answer is


\frac{5}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^3}{6^3}


Third question:

To get exactly one six, it can either be the first, second or third roll.


In all cases, you have to choose the left path once and the right path twice: left-right-right mean that you get the six in the first roll, right-left-right means that you get the six in the second roll, right-right-left means that you get the six in the third roll.


In every case, the left turn has probability 1/6, and the right turn has probability 5/6. The probability of each combination is thus


\frac{1}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^2}{6^3}


And since there are three of these combinations, The answer is


3\frac{5^2}{6^3}


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1 - \frac{5^3}{6^3}

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Answer:

Step-by-step explanation:

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6 0
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The last one need the right answer please
Llana [10]

Answer:

Part 1) The unit rate is 16\frac{dollars}{ounce}

Part 2) The unit rate is \frac{1}{4}\frac{dollars}{ounce}

Part 3) The unit rate is \frac{1}{4}\frac{dollars}{ounce}

Part 4) The unit rate is 4\frac{dollars}{ounce}

see the attached figure

Step-by-step explanation:

we know that

The formula to calculate the slope between two points is equal to

m=\frac{d2-d1}{n2-n1}

where

d ----> number of dollars (dependent variable or output value)

n ---> number of ounces (independent variable or input value)

Remember that the slope of the linear equation is the same that the unit rate

<u><em>Verify each case</em></u>

1) we have

d=16n

This is a proportional relationship between the variables d and n

The slope is

m=16\frac{dollars}{ounce}

therefore

The unit rate is 16\frac{dollars}{ounce}

2) we have

<em>First table</em>

take two points from the table

(4,1) and (16,4)

substitute in the formula of slope

m=\frac{d2-d1}{n2-n1}

m=\frac{4-1}{16-4}

m=\frac{3}{12}\frac{dollars}{ounce}

simplify

m=\frac{1}{4}\frac{dollars}{ounce}

therefore

The unit rate is \frac{1}{4}\frac{dollars}{ounce}

3) we have

n=4d

This is a proportional relationship between the variables d and n

isolate the variable d

d=\frac{1}{4}n

The slope is

m=\frac{1}{4}\frac{dollars}{ounce}

therefore

The unit rate is \frac{1}{4}\frac{dollars}{ounce}

4) we have

<em>Second table</em>

take two points from the table

(1,4) and (2,8)

substitute in the formula of slope

m=\frac{d2-d1}{n2-n1}

m=\frac{8-4}{2-1}

m=4\frac{dollars}{ounce}

therefore

The unit rate is 4\frac{dollars}{ounce}

5 0
4 years ago
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