19. Perimeter of rectangle = 2(l + b)
l = 25m
b = 16m
Perimeter of rectangular park = 2 (25 + 16)
= 50 + 32
= 82m
Perimeter of square park = 82m
(given that, perimeter of rectangular and square park are equal)
Perimeter of square = 4a
4a = 82
a = 82/4
a = 20.5m
Area of square park = a²
= 20.5²
= 420.25m²
20. Perimeter of regular hexagon = 6a
a = 2.5
6a = 6 × 2.5
= 15cm
21. Perimeter of regular decagon = 10a
a = 8
10a = 10 × 8
= 80cm
Answer:
259.6 ft/sec
Step-by-step explanation:
it is a universal standard that acceleration due to gravity is 32ft/sec^2.
Now it can be verified by equation,
V(f) = V(i)+at (1st equation of motion derived by Newton's three laws of motion)
where,
V(f) is final velocity
V(i) is initial velocity
a is acceleration which is constant and have value 32ft/sec^2
t is time which is given as 7.8 seconds
In the given case, initial velocity that is V(i) will be 0ft/sec. Because, on dropping, object will start to move under the influence of gravity from zero speed.
So,
V(f) = 0 +(32) (7.8)
V(f) = 249.6 ft/sec
Now the condition is given that you have to add a constant 10 to the answer.
so, V(f) = 249.6 + 10
V(f) = 259.6 ft/sec
Answer:
Hello There!!
Step-by-step explanation:
0.04×0.005=0.0002
.0002 ✔
(4/100)=>0.04 × (5/1000)=>0.005=0.0002 ✔
(4 × .01)=>0.04 × (5 × .001)=>0.0005 =0.00002 ❌
.002 ❌
4 × 5 × .00001=0.0002 ✔
hope this helps,have a great day!!
~Pinky~
Honestly? Just review your notes and try to work out the problems yourself before taking a look at the answer. You can also google specific topics that the test will cover and try the practice problems.
Given :
- The length of a rectangle is 4m more than the width.
- The area of the rectangle is 45m²
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To Find :
- The length and width of the rectangle.
⠀
Solution :
We know that,
So,
Let's assume the length of the rectangle as x and the width will be (x – 4).
⠀
Now, Substituting the given values in the formula :
⠀
Since, The length can't be negative, so the length will be 9 which is positive.
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