Write the additive inverse and multiplicative inverse of 3-7i?
1 answer:
Step-by-step explanation:
additive inverse means multiplying 3-7i by it's conjugate which would be
(3-7i)(3+7i)=3^2+7^2=9+49=58
the multiplicative inverse of a number z is 1/z
1/(3-7i)
multiply numerator and denominator by 3-7i's conjugate and it equals 58
(3-7i)/58
3/58-7/58i
Hope that helps :)
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