Answer: (9, 9)
Step-by-step explanation:
Complete question :
A random sample of n = 83 measurements is drawn from a binomial population with probability of success 0.4 . Complete parts a through d below. a. Give the mean and standard deviation of the sampling distribution of the sample proportion, . The mean of the sampling distribution of is nothing. The standard deviation of the sampling distribution of is nothing.
Answer:
Mean = 33.2000
Standard deviation = 4.4632
Step-by-step explanation:
Given that :
Sample size (n) = 83
Probability of success (p) = 0.4
q = p' = (1 - p) = 1 - 0.4 = 0.6
The mean of the sampling distribution :
Sample size * probability of success
n * p = 83 * 0.4 = 33.2000
The standard deviation of the sampling distribution :
σ=√(sample size * probability of success * (1 - p))
σ = √n * p * (1 - p)
σ = √(83 * 0.4 * 0.6)
σ = √19.92
σ = 4.46318
σ = 4.4632
Answer:
No
Step-by-step explanation:
49 ≥ 10d
49 ≥ 10(8)
49 ≥ 80
49 has to be greater than or equal to 80
d = 8 isn’t a solution
Answer:
I believe it's A) 5x + 6y = 58 8x + 11y = 97
Step-by-step explanation:
Reason is, adult tickets and child tickets are two different things, so they require two different variables, and two different equations because they have two different sums. (This was probably already obvious to you though).
Hope this helps :)
I tried my best to explain.
3y + 5.2 = 2 - 5y
3y + 5y + 5.2 = 2
8y = 2 - 5.2
8y = -3.2
y = (-3.2) / 8
y = -0.4
