HURRY Choose the compatible numbers that will give the best estimate for 641/59 HURRRRRRRYYY
1 answer:
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The linear relationship which exists between the change in weight and number of days of hibernation in a hedgedog can be modeled using the equation y = - 0.03 + 0
- Change in weight per day of hibernation = - 0.03
- Change in weight for 115 days = - 3.45 ounces
A linear model can be created using the data in the table given using a regression calculator or excel ;
The linear model obtained in the form y = m + bx is :
- y = - 0.03x + 0
- y = change in weight
- x = number of days of hibernation
- Intercept = 0
- Slope = -0.03
- The slope value of the function gives the change in weight value per number of days of hibernation ; which is -0.03.
- Using the regression equation, substitute, the vlaue of x = 115
- -0.03(115) + 0 = - 3.45
Therefore, the change in weight after 115 days of hibernation is - 3.45 ounces.
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Answer:
The car must have a speed of 25 kilometres per hour to stop after moving 7 metres.
Step-by-step explanation:
Let be , where
is the stopping distance measured in metres and
is the speed measured in kilometres per hour. The second-order polynomial is drawn with the help of a graphing tool and whose outcome is presented below as attachment.
The procedure to find the speed related to the given stopping distance is described below:
1) Construct the graph of .
2) Add the function .
3) The point of intersection between both curves contains the speed related to given stopping distance.
In consequence, the car must have a speed of 25 kilometres per hour to stop after moving 7 metres.
