The answer is B)allopatric speciation.
1) Data:
dominant allele- A
recessive allele- a
Heterozygotic: Aa (only carries the allele)
Homozygotic recessive: aa (expresses the disease)
Homozygotic dominant: AA (doesn't carry or expresses the disease)
2)The first cross between Jim and his first wife originated a offspring with
<span>cystic fibrosis</span>. That offspring has the genotype aa and for that to happen both parents need to be a least carriers or express the disease. The exercise rules out the second case, which makes Jim a carrier.
3)Now between Jim and Martha:
From the previous step, we already found that jim is a carrier and the exercise also tells us that Martha is one too. So, their genotype is: Aa.
The cross: Aa x Aa
The probability:
1/4 aa = 25%
2/4 =Aa
1/4 - AA
the probability of having a <span>baby with cystic fibrosis is 25%</span>
This interaction is best described as parasitic
I would explain it by saying that most groups, other than generally white males, were once underprivileged, and over time gained their rights. For example, racial minorities like African Americans have continued to gain rights over time including the abolition of slavery and the end of official segregation
