Average rate of change over interval [a,b]: r=[f(b)-f(a)]/(b-a)
In this case the interval is [0,2], then a=0, b=2
r=[f(2)-f(0)]/(2-0)
r=[f(2)-f(0)]/2
1) First function: h(x)
r=[h(2)-h(0)]/2
x=2→h(2)=(2)^2+2(2)-6
h(2)=4+4-6
h(2)=2
x=0→h(0)=(0)^2+2(0)-6
h(0)=0+0-6
h(0)=-6
r=[h(2)-h(0)]/2
r=[2-(-6)]/2
r=(2+6)/2
r=(8)/2
r=4
2) Second function: f(x)
A function, f, has an
x-intercept at (2,0)→x=2, f(2)=0
and a y-intercept at (0,-10)→x=0, f(0)=-10
r=[f(2)-f(0)]/2
r=[0-(-10)]/2
r=(0+10)/2
r=(10)/2
r=5
3) Third function: g(x)
r=[g(2)-g(0)]/2
From the graph:
g(2)=6
g(0)=2
r=(6-2)/2
r=(4)/2
r=2
4) Fourth function: j(x)
r=[j(2)-j(0)]/2
From the table:
x=2→j(2)=-8
x=0→j(0)=4
r=(-8-4)/2
r=(-12)/2
r=-6
Answer:
Pairs
1) h(x) 4
2) f(x) 5
3) g(x) 2
4) j(x) -6
Answer:
2m^3n^3
Step-by-step explanation:
Let us start with the number parts
36 , 2 and 4
2 is common here as it can divide all
The smallest m factor is m^3 so it is common for all
The smallest n factor is n^3 which is also common for all
So, we have the greatest common factor as;
2 * m^3 * n^3 = 2m^3n^3
Answer: number of tickets sold to adult = 566
Step-by-step explanation:
Let x = number of tickets sold by DCHS to students.
Let y = number of tickets sold DCHS to adults.
Tickets to Dundee crowns mr.dchs are $3 for students and $5 for adults.
This means cost of total tickets sold to students and adults is $3x and $5y respectively.
If DCHS collected $3943 for the tickets, then we have
3x + 5y = 3943 - - - - - -1
The number of adult tickets sold was 195 more than the number of student tickets. This means
y = x +195.
Put y = x +195 in equation 1
3x + 5(x+195) = 3943
3x + 5x + 975= 3943
8x +975=3943
8x = 3943-975= 2968
x = 2968/8 = 371
y = 371 + 195= 566
Answer:
7 hours
Step-by-step explanation:
90 divided by 5 is 18 so 126 divideded by 18 is7
