Answer:
35 minutes
Step-by-step explanation:
The total amount of water is 200 +60 = 260 gallons. The two tanks will have equal amounts when each has half that, or 130 gallons.
If the volume in tank 2 is increasing at 2 gallons per minute, it will increase by 70 gallons from 60 gallons to 130 gallons in 70/2 = 35 minutes.
Answer:
35/20
Step-by-step explanation:
20 divided by 4 = 5
so our multiple is 5
5 x 4 = 20
so we have to do the same to the numerator
5 x 7 = 35
Simplified= 1 3/5
Answer:
111
Step-by-step explanation:
il help u if u help me look at my thing and ill help u
Answer:
well we know d>30 and 1.00>d
so i think the answer would be just that d>30=1.00>d
Step-by-step explanation:
We have to assume that the speed before being stuck was sufficient to get to the destination on time had there been no delay. Call that speed "s" in km/h.
Since 200 km is "halfway", the total distance must be 400 km.
time = distance / speed
total time = (time for first half) + (delay) + (time for second half)
400/s = 200/s + 1 + 200/(s+10) . . . .times are in hours, distances in km
200/s = 1 + 200/(s+10) . . . . . . . . . . subtract 200/s
200(s+10) = s(s+10) +200s . . . . . . .multiply by s(s+10)
0 = s² +10s - 2000 . . . . . . . . . . . . . .subtract the left side
(s+50)(s-40) = 0
Solutions are s = -50, s = 40
The speed of the bus before the traffic holdup was 40 km/h.
