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tamaranim1 [39]
3 years ago
6

Need help here plss

Mathematics
1 answer:
goldenfox [79]3 years ago
4 0

Answer:

see below

Step-by-step explanation:

Thankfully, these inequalities are already simplified, so all we have to do here is graph the inequalities as they are.

To graph y > 2x - 3, first draw the line y = 2x - 3. Make sure to make the line dashed because the sign is ">", which means that the points on the line do not belong to the solution set. Now, we need to figure out which side of the line to shade on. Since the sign is ">", that means that we will shade "above" the line, or on the left side of it. (This is the blue area in the image.)

Repeat a similar process to graph y < x + 1. As usual, first draw the line y = x + 1, and again, make it a dashed line since the sign is "<". And since the sign is "<", that means that we will shade "below" the line, or on the right side of it. (This is the red area in the image.)

The solution set to this system is the area where the two shaded areas overlap, which is the purple area in the image below. Hope this helps!

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-2.1b +5.3= b -- 3.1b + 5.3<br><br> does is have one solution or infinitely many solutions ? Why ?
pychu [463]

Answer: infinitely many solutions.

Step-by-step explanation:

Ok, our equation is:

-2.1*b + 5.3 = b - 3.1*b + 5.3

now, simplifyng the right side, we have:

b - 3.1*b + 5.3 = (1 - 3.1)*b + 5.3 = -2.1*b + 5.3

Then our initial expression is:

-2.1*b + 5.3 = -2.1*b + 5.3

So in both sides of the equality we have the exact same thing, so this is a trivial equality.

This means that the equality will remain true for any value of b, which means that we have infinitely many solutions.

6 0
3 years ago
Find the volume of the solid under the plane 5x + 9y − z = 0 and above the region bounded by y = x and y = x4.
svp [43]
<span>For the plane, we have z = 5x + 9y

For the region, we first find its boundary curves' points of intersection.
x = x^4 ==> x = 0, 1.

Since x > x^4 for y in [0, 1],

The volume of the solid equals

\int\limits^1_0 { \int\limits_{x^4}^x {(5x+9y)} \, dy } \, dx = \int\limits^1_0 {\left[5xy+ \frac{9}{2} y^2\right]_{x^4}^{x}} \, dx  \\  \\ =\int\limits^1_0 {\left[\left(5x(x)+ \frac{9}{2} (x)^2\right)-\left(5x(x^4)+ \frac{9}{2} (x^4)^2\right)\right]} \, dx  \\  \\ =\int\limits^1_0 {\left(5x^2+ \frac{9}{2} x^2-5x^5- \frac{9}{2} x^8\right)} \, dx =\int\limits^1_0 {\left( \frac{19}{2} x^2-5x^5- \frac{9}{2} x^8\right)} \, dx \\  \\ =\left[ \frac{19}{6} x^3- \frac{5}{6} x^6- \frac{1}{2} x^9\right]^1_0

=\frac{19}{6} - \frac{5}{6} - \frac{1}{2} =\bold{ \frac{11}{6} \ cubic \ units}</span>
8 0
3 years ago
Determine if the ordered pair (6, 4) is a solution to the inequality
Ugo [173]

Answer:

\Large \boxed{\mathrm{Option \ D}}

Step-by-step explanation:

(6, 4)

x = 6 and y = 4

y > -1/2x + 7

Plug in the values to check if it is true.

4 > -1/2(6) + 7

4 > -3 + 7

4 > 4

This statement is false.

(6, 4) lies on the line.

8 0
3 years ago
What is the value of 1/3 +7x, when x = 5
CaHeK987 [17]
1/3 + 7x = 1/3 + 7(5 )=
1/3+35
=1/3 + 105/3 =
106/3=
35 1/3
3 0
3 years ago
Read 2 more answers
Greater 3/5 or .5625
labwork [276]

Answer: 3/5

Step-by-step explanation: 3/5 is equal to .6 so if is greater than .5625

6 0
3 years ago
Read 2 more answers
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