Answer:
f(x) = 3/5x + 1
Step-by-step explanation:
<u>Change in y</u>
Change in x
<u>4 - 1</u>
5 - 0
<u>3</u>
5
well, p + (-2), now a sign in front of a grouping symbol usually means it has a 1*, so +(, really means +1*, thus p + (-2) really means p + 1*(-2), which gives us p - 2, and that'd be ordinally, 2 numbers to the left of "p".
likewise, 5 + p, is just the same as p + 5, so that value will be a number 5 numbers to the right of "p".
just as above, p + 1, is just one value to the right of "p".
![\bf \rule[0.35em]{2em}{0.25pt}\stackrel{p-2~\hfill }{|\rule[0.35em]{2em}{0.25pt}}|\rule[0.35em]{2em}{0.25pt}\boxed{P}\stackrel{~\hfill p+1}{\rule[0.35em]{2em}{0.25pt}|}\rule[0.35em]{2em}{0.25pt}|\rule[0.35em]{2em}{0.25pt}|\rule[0.35em]{2em}{0.25pt}|\stackrel{~\hfill p+5}{\rule[0.35em]{2em}{0.25pt}|}\rule[0.35em]{2em}{0.25pt}|](https://tex.z-dn.net/?f=%5Cbf%20%5Crule%5B0.35em%5D%7B2em%7D%7B0.25pt%7D%5Cstackrel%7Bp-2~%5Chfill%20%7D%7B%7C%5Crule%5B0.35em%5D%7B2em%7D%7B0.25pt%7D%7D%7C%5Crule%5B0.35em%5D%7B2em%7D%7B0.25pt%7D%5Cboxed%7BP%7D%5Cstackrel%7B~%5Chfill%20p%2B1%7D%7B%5Crule%5B0.35em%5D%7B2em%7D%7B0.25pt%7D%7C%7D%5Crule%5B0.35em%5D%7B2em%7D%7B0.25pt%7D%7C%5Crule%5B0.35em%5D%7B2em%7D%7B0.25pt%7D%7C%5Crule%5B0.35em%5D%7B2em%7D%7B0.25pt%7D%7C%5Cstackrel%7B~%5Chfill%20p%2B5%7D%7B%5Crule%5B0.35em%5D%7B2em%7D%7B0.25pt%7D%7C%7D%5Crule%5B0.35em%5D%7B2em%7D%7B0.25pt%7D%7C)
Triple 4 is just 12
4X3=12
And so you can then divide by 2 because 2 each day(you could also just keep subtracting). Either way, you get 6 days
Answer:
-7, -0
Step-by-step explanation:
Yes it is possible to prove this is a parallelogram.
XN = NZ means the diagonal XZ has been bisected
The same goes for diagonal WY (because NY = NW)
Furthermore, we have the pair of vertical angles XNY and ZNW which are congruent
Through SAS, we can say that triangles XNY and ZNW are congruent
Using CPCTC, we can get to the fact that angle NWZ = angle NYX which are alternate interior angles leading to proving that XY || WZ
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If you repeat those steps above, but focus on triangles WNX and YNZ, we can prove that XW || YZ
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After proving that XY || WZ and XW || YZ, this is enough to prove we have a parallelogram as the opposite sides are parallel.
