Probability please help! (Picture)

A number cube is rolled three times. What is the probability of rolling three even numbers?

ziro4ka [17]

It depends on how many numbers are on the cube. If the cube goes up to five then you have a 2/5 chance to roll an even number one time. If the dice goes up to 10 then you have 5/10 chance of rolling an even number.

6 0

3 years ago

1.Famous basketball player Michael Jordan had a free throw percentage of 0.83. (He made 83% of his free throw shots.) Assume tha

MissTica

Michael Jordan's Freethrow, the population of the 6 countries and the distribution of the uninsured drivers are illustrations of probabilities

<h3>1. Michael Jordan Freethrow</h3>

The given parameter is:

p = 83% -- the percentage of free throws he made

<u>Probability that he misses his 6th throw </u>

The probability that he misses his 6th throw is:

P = P(He made the first 5 throws) * P(He lost the 6th)

This gives

P = (83%)^5 * (1 - 83%)^1

P = 0.0670

<u>Expected number of miss</u>

The expected number till he misses the first free throw is:

E(x) = np

This gives

E(x) = 6 * 83%

E(x) = 4.98

Approximate

E(x) = 5

Hence, the probability that he misses his 6th throw is 0.0670 and the expected number till he misses the first free throw is 5

<h3>2. Country Populations</h3>

The given parameters are:

Average population = 268.35 million

Standard deviation = 370.43 million

<u>The z-scores for the United States, Egypt, and Mexico</u>

This is calculated as:

z = (x - $\mu$ )/ $\sigma$

So, we have:

US = (332 million - 268.35 million)/ 370.43 million

US = 0.17

Egypt = (104 million - 268.35 million)/ 370.43 million

Egypt = -0.44

Mexico = (128 million - 268.35 million)/ 370.43 million

Mexico = -0.38

<u>The countries from the smallest to the largest </u>

By comparing the z-score of the countries, the order of the countries are:

Egypt, Japan, Mexico, Brazil, United States and India

The countries are ranked that way because the higher the z-score, the higher the population

<h3>3. Uninsured drivers</h3>

The given parameter is:

p = 12.6% -- the percentage of uninsured drivers

<u>Probability that exactly 5 drivers of 30 are uninsured</u>

This is calculated as:

P(x) = nCx * p^x * (1 - p)^(n-x)

So, we have:

P(5) = 30C5 * (12.6%)^5 * (1 - 12.6%)^(30-5)

Evaluate the product

P(5) = 0.1561

<u>Probability that the next uninsured driver is the 7th</u>

This is calculated as:

P = P(First 6 are insured) * P(7th is unisured)

This gives

P = (1 - 12.6%)^6 * (12.6%)^1

P = 0.0562

The probability that exactly 5 drivers of 30 are uninsured is 0.1561, and the probability that the next uninsured driver is the 7th is 0.0562