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3 years ago

Is this a valid experimental design? A. B. C. D.

Mathematics

2 answers:

Marrrta [24]3 years ago

6 0

Answer: d

Step-by-step explanation: None needed

vagabundo [1.1K]3 years ago

3 0

Answer:

i would say 3

Step-by-step explanation: why? because most likely they are testing 2 different types and if one gets a unfair advantage that can ruin everything

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What's 23 x 5/8 I need help

vitfil [10]

14 3/8
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3 0

3 years ago

Read 2 more answers

2 *p2 + 3s for p = 3 and s = 11

maw [93]

Answer:

Step-by-step explanation:

Order of Operations: BPEMDAS

Step 1: Write out equation

2p² + 3s

Step 2: Define variables

p = 3

s = 11

Step 3: Replace variables

2(3)² + 3(11)

Step 4: Evaluate

2(9) + 33

18 + 33

8 0

4 years ago

A football team lost 5 yards on each if 3 plays. Find the teams change in the position after the 3 plays.

Lady_Fox [76]

Answer:

They lost 5 yards.

Step-by-step explanation:

Every three plays leads to loosing 5 years and after three plays that means they are five years back.

6 0

3 years ago

Factor 4x^2 + 1x – 13

bulgar [2K]

Answer:

$(x - \frac{\sqrt{209} - 1}{8} )(x - \frac{-1 - \sqrt{209} }{8} )$

Step-by-step explanation:

FACTS TO KNOW BEFORE SOLVING :-

Quadratic Formula :-

Lets say , there's an equation ax² + bx + c.

$=> x = \frac{-b + \sqrt{b^2 - 4ac} }{2a} \: or \: \frac{-b - \sqrt{b^2 - 4ac} }{2a}$

SOLUTION :-

According to the question ,

a (Coefficient of x²) = 4

b (Coefficient of x) = 1

c (constant) = -13

By using quadratic formula ,

$x = \frac{-1 + \sqrt{1^2 - 4 \times 4 \times (-13)} }{2 \times 4} \: or \: \frac{-1 - \sqrt{1^2 - 4 \times 4 \times (-13)} }{2 \times 4}$

$=> x = \frac{-1 + \sqrt{209} }{8} \: or \: \frac{-1 - \sqrt{209} }{8}$

$=> (x - \frac{\sqrt{209} - 1}{8} ) \: and \: (x - \frac{-1 - \sqrt{209} }{8} )$ are the factors of 4x² + x - 13.

6 0

3 years ago

Sup people can you help me here.

Sedaia [141]

The answer would be -6

3 0

3 years ago