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PSYCHO15rus [73]
3 years ago
7

Sin^2x=1/4. Find all solution on the interval [0,2pi).

Mathematics
1 answer:
steposvetlana [31]3 years ago
4 0
I really don’t know I’m just answering questions that I know sorry
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Can someone help me?
svlad2 [7]

Answer:

Use Pythagorean theorem,

Hypotenuse² = base² + altitude²

= 3²+ 6²

= 9 + 36

x² = 45

x = √45

x = 6.71

Step-by-step explanation:

7 0
3 years ago
Find the exact circumference of a circle with the given radius.
kozerog [31]
We know, Circumference = 2π * x/2 = <span>π x

In short, Your Answer would  be: Option B

Hope this helps!</span>
8 0
3 years ago
Read 2 more answers
#2) Jane wants to have a test average of at least 78.
Vlad [161]
She would have to score atleast a 74 on the test for her average to be 78
5 0
3 years ago
(7z^3+42z^2-15z+1)- (36z^2+12z-21)​
My name is Ann [436]

Answer:

7z^3+6z^2-27z+22

Step-by-step explanation:

The given question is of subtraction:

So,

(7z^3+42z^2-15z+1)- (36z^2+12z-21)​

=7z^3+42z^2-15z+1-36z^2-12z+21

Combining alike terms to simplify

=​7z^3+42z^2-36z^2-15z-12z+1+21

=7z^3+6z^2-27z+22

So the answer in simplified form is:

7z^3+6z^2-27z+22 ..

6 0
3 years ago
Read 2 more answers
Explain steps ASAP please and thank you
iren [92.7K]

Answer:

5\sqrt{8}

24\sqrt{3}

Step-by-step explanation:

To simplify the square roots, break the number under the square root into factors. Any factors which are perfect squares may be simplified to outside the square root.

\sqrt{200}=\sqrt{25*8}  =\sqrt{25}*\sqrt{8}= 5*\sqrt{8}   =5\sqrt{8}

and

4\sqrt{108}=4\sqrt{27*4}  =4*\sqrt{27}*\sqrt{4}=4* \sqrt{9} *\sqrt{4}*\sqrt{3}    =4*3*2*\sqrt{3}=24\sqrt{3}

7 0
3 years ago
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