Answer:
<em>79,920 different ways</em>
Step-by-step explanation:
Combination has to do with selection:
If we are to select 3 teachers from a pool of 10 teachers to form a committee, this can be done in 10C3 number of ways.
10C3 = 10!/(10-3)!3!
10C3 = 10!/7!3!
10C3 = 10*9*8*7!/7!3!
10C3 = 10*9*8/3*2
10C3 = 720/6
10C3 = 120 ways
Similarly, selecting five 2 students from a pool of 37 students to form a committee, this can be done in 37C2 difference ways;
37C2 = 37!/(37-2)!2!
37C2 = 37!/35!2!
37C2 = 37*36*35!/35!*2
37C2 = 37*36/2
37C2 = 37 * 18
37C2 = 666 ways
<em>Hence the total number of ways that the 5 committees can be selected is expressed as 10C3 * 37C3 = 120 * 666</em>
<em> 120 * 666 = 79,920 ways</em>
Answer:
B) (-2,1)
Step-by-step explanation:
The solution is where the two lines intersect, in this case at (-2,1)
Hope this helps! :)
Answer:
I think 32% (Let me know if I am wrong)
Step-by-step explanation:
Answer:
iii) Use algebraic methods
Step-by-step explanation:
There are various method of finding an accurate solution to a system of linear equations.
They are i) graphing method: ii) algebraic method: iii) Matrices method:
iv) determinant method: v) guess method vi) Cramer's rule etc
Guess and check is not reliable because guess is possible only for integers or numbers with 1 or 2 decimals. SOmetimes guess may give unreliable results. And every time after the guess, checking and verifying will be time consuming and laborious
Graphing the lines may be accurate but writing tables for each line, choosing scales and drawing lines to find points of intersection may be time consuming.
Algebraic methods using are easy to understand, reliable, and less time consuming but 100% accuracy. There are a number of ways in algebraic method also such as substitution, elimination or cross multiplication, etc
Thus option iii) is right