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ivanzaharov [21]
2 years ago
14

Sorry i'm the most non-smart person on the planet someone help me please! PLease show work.

Mathematics
1 answer:
Tpy6a [65]2 years ago
5 0

Answer:

25

Step-by-step explanation:

The whole straight line is 180 And the angles are adjacent.

180-125 which equals 55

trying to find X so subtract 30

55-30=25

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uysha [10]

Answer:

C

Step-by-step explanation:

Hello There!

so

y = -5x^2 + 8x +4

where y = height of ball and x = seconds after ball was thrown

The plus 4 is the y intercept and because y equals height of ball the 4 would represent the height that the ball was thrown at

<em>~TheMathWiz</em>

3 0
3 years ago
Archie and his friends went scuba diving. Each person recorded his dive depth. If land represents 0, which dive depth is closest
Mariana [72]
-20 feet



that would be the number closest to 0
4 0
3 years ago
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Please explain the steps or this equation 3+p=8
ladessa [460]

Answer:

5

Step-by-step explanation:

We can subtract both sides of the equation by 3, getting 3 + p - 3 = 8 - 3.

Then we can evaluate, getting p = 8 - 3 = 5.

3 0
3 years ago
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NO LINKS!!
dexar [7]

Answer: Anything between 0 and 10, excluding both endpoints.

In terms of symbols we can say 0 < w < 10 where w is the width.

===================================================

Explanation:

You could do this with two variables, but I think it's easier to instead use one variable only. This is because the length is dependent on what you pick for the width.

w = width

2w = twice the width

2w-5 = five less than twice the width = length

So,

  • width = w
  • length = 2w-5

which lead to

area = length*width

area = (2w-5)*w

area = 2w^2-5w

area < 150

2w^2 - 5w < 150

2w^2 - 5w - 150 < 0

To solve this inequality, we will solve the equation 2w^2-5w-150 = 0

Use the quadratic formula. Plug in a = 2, b = -5, c = -150

w = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\w = \frac{-(-5)\pm\sqrt{(-5)^2-4(2)(-150)}}{2(2)}\\\\w = \frac{5\pm\sqrt{1225}}{4}\\\\w = \frac{5\pm35}{4}\\\\w = \frac{5+35}{4} \ \text{ or } \ w = \frac{5-35}{4}\\\\w = \frac{40}{4} \ \text{ or } \ w = \frac{-30}{4}\\\\w = 10 \ \text{ or } \ w = -7.5\\\\

Ignore the negative solution as it makes no sense to have a negative width.

The only practical root is w = 10.

If w = 10 feet, then the area = 2w^2-5w results in 150 square feet.

----------------------

Based on that root, we need to try a sample value that is to the left of it.

Let's say we try w = 5.

2w^2 - 5w < 150

2*5^2 - 5*5 < 150

25 < 150 ... which is true

This shows that if 0 < w < 10, then 2w^2-5w < 150 is true.

Now try something to the right of 10. I'll pick w = 15

2w^2 - 5w < 150

2*15^2 - 5*15 < 150

375 < 150 ... which is false

It means w > 10 leads to 2w^2-5w < 150  being false.

Therefore w > 10 isn't allowed if we want 2w^2-5w < 150 to be true.

4 0
2 years ago
Can someone please check and see if these are correct 11-15
Allushta [10]

Answer:

All of them are correct except for number 15

Step-by-step explanation:

Number 15 is D.

6 0
3 years ago
Read 2 more answers
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