Considering the slopes of the given lines, they are parallel lines.
<h3>When are lines parallel, perpendicular or neither?</h3>
The slope, given by <u>change in y divided by change in x</u>, determines if the lines are parallel, perpendicular, or neither, as follows:
- If they are equal, the lines are parallel.
- If their multiplication is of -1, they are perpendicular.
- Otherwise, they are neither.
The first line, in standard form, is given by:
5y = x + 5
y = 0.2x + 1.
The slope is of m = 0.2.
For the second line, we have that:
25y = 5x - 75
y = 0.2x - 3
The slope is of m = 0.2.
Same slope, hence the lines are parallel.
More can be learned about the slope of a line at brainly.com/question/12207360
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Find a number that goes into both numbers. There are none for this example. So 33/128 is in it's simplest form
A function does not have an "answer." In this case you are asked to simplify the given function as much as possible, not to "answer" it.
If f(x) = 2[sqrt(x)] + 1
the only possible simplification is to omit the brackets [ ]:
f(x) = 2sqrt(x) + 1. END
Answer:
Hence after period of 9 years from 1990 t0 1999 will be 61438 rabbits.
Step-by-step explanation:
Given:
Population for rabbit obeys exponential law.
120 at 1990 and 240 1991 ...after 1 year time period
To Find:
After 9 year time period how many rabbits will be there.
Solution:
Exponential law goes on present value and various value and time period and defined as ,
let Y be present value Y0 previous year value and k exponential constant and t be time period.
So
Y=Y0e^(kt)
Here Y=240 ,Y0=120 t=1 year time period
So
240=120e^(k*1)
240/120=e^k
2=e^k
Now taking log on both side, [natural log]
ln(2)=ln(e^k)
ln(2)=kln(e)
k=ln(2)
k=0.6931
For t=9 year of time period
Y0=120, t=9 ,k=0.6931
Y=Y0e^(k*t)
Y=120*e^(0.6931*9)
=120e^6.2383
=61438.48
=61438 rabbits
Answer: answer is 19.2
a squared + b squared = c2
81 + 289 = 370
square root of 370 = 19.235
answer is 19.2
