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Aleonysh [2.5K]

3 years ago

7

Which statements about the hyperbola are true? Check all that apply. There is a vertex at (–5, 2). The center of the hyperbola i

s at (–2, 2). There is a vertex at (–2, 7). The transverse axis is vertical. The directrices are vertical lines.

2 answers:

skelet666 [1.2K]3 years ago

4 0

Answer:

A, B, E,

Step-by-step explanation:

CAuse yes

hammer [34]3 years ago

4 0

all but c

thats the answer

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5(x + y) -3( x - y)=

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5(x + y) - 3(x - y)

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7 0

3 years ago

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What value of x is in the solution set of 2x – 3 > 11 – 5x?<br><br> –3 <br> 0<br> 2<br> 4

Makovka662 [10]

Answer:

x = 4

Step-by-step explanation:

Solve the inequality

2x - 3 > 11 - 5x ( add 5x to both sides )

7x - 3 > 11 ( add 3 to both sides )

7x > 14 ( divide both sides by 7 )

x > 2

The only value of x greater than 2 is 4, thus

x = 4 is in the solution set

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3 years ago

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Helpppp me please!!!

Semenov [28]

To find the value of q, we need to find d(-8). Put another way, we need to find the value of d(x) when x = -8

$d(x) = -\sqrt{\frac{1}{2}x+4}$

$d(-8) = -\sqrt{\frac{1}{2}(-8)+4}$

$d(-8) = -\sqrt{-4+4}$

$d(-8) = -\sqrt{0}$

$d(-8) = 0$

So this means q = 0. Note that -0 is just 0.

===========================================

The value of r will be a similar, but now we use f(x) this time.

Plug in x = 0

$f(x) = \sqrt{\frac{1}{2}x+4}$

$f(0) = \sqrt{\frac{1}{2}*0+4}$

$f(0) = \sqrt{0+4}$

$f(0) = \sqrt{4}$

$f(0) = 2$

Therefore, r = 2.

===========================================

For s, we plug x = 10 into f(x)

$f(x) = \sqrt{\frac{1}{2}x+4}$

$f(10) = \sqrt{\frac{1}{2}*10+4}$

$f(10) = \sqrt{5+4}$

$f(10) = \sqrt{9}$

$f(10) = 3$

So s = 3.

===========================================

Finally, plug x = 10 into d(x) to find the value of t

$d(x) = -\sqrt{\frac{1}{2}x+4}$

$d(10) = -\sqrt{\frac{1}{2}(10)+4}$

$d(10) = -\sqrt{5+4}$

$d(10) = -\sqrt{9}$

$d(10) = -3$

A shortcut you could have taken is to note how d(x) = -f(x), so this means

d(10) = -f(10) = -9 since f(10) = 9 was found in the previous section above.

Whichever method you use, you should find that t = -3.

===========================================

<h3>In summary:</h3><h3>q = 0</h3><h3>r = 2</h3><h3>s = 3</h3><h3>t = -3</h3>

8 0

3 years ago