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Aleonysh [2.5K]
3 years ago
7

Which statements about the hyperbola are true? Check all that apply. There is a vertex at (–5, 2). The center of the hyperbola i

s at (–2, 2). There is a vertex at (–2, 7). The transverse axis is vertical. The directrices are vertical lines.
Mathematics
2 answers:
skelet666 [1.2K]3 years ago
4 0

Answer:

A, B, E,

Step-by-step explanation:

CAuse yes

hammer [34]3 years ago
4 0

all but c

thats the answer

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Help answer asap pls ---------
Reika [66]

Answer:

d = 5

Step-by-step explanation:

We want to know what d would be when x = -1, so we can start off by plugging in -1 for x to get the following equation: \sqrt{8 - (-1)} = 2(-1)+d. On the left hand side, 2 negatives become a positive sign, so the -(-1) becomes a +1, and 8+1 would equal 9. On the right hand side, we just multiply 2 and -1 to get -2. So, the equation now looks like this: \sqrt{9} = d-2. We know that \sqrt{9} = 3, so we would get 3 = d-2. THen we would add 2 to both sides to get d = 5. Hope this helps!

8 0
3 years ago
<img src="https://tex.z-dn.net/?f=108cm%20%7B%3F%7D%5E%7B2%7D%20" id="TexFormula1" title="108cm {?}^{2} " alt="108cm {?}^{2} " a
scoundrel [369]
A(base)=6*6=36
A( triangle)=1/2*(base of the triangle)*height( of the triangle)=1/2*6*4=12
one base +4 triangles=36+4*12=36+48 =84 cm²
8 0
3 years ago
Please answer this question!!
n200080 [17]
B. 273.18  is the correct answer I think.

6 0
3 years ago
He mathematics department of a college has 6 male​ professors, 8 female​ professors, 14 male teaching​ assistants, and 7 female
irinina [24]
Total number of people in the department = 6 + 8 + 14 + 7 = 35
Total males = 6 + 14 = 20
Total female professor = 8
Total males or professor = 20 + 8 = 28

P(\text {male or professor}) =  \dfrac{28}{35} =  \dfrac{4}{5}

\boxed {\boxed {\text {Answer: P(male or professor) = }\dfrac{4}{5} }}
3 0
3 years ago
a whisper volume as a room that allows two people to stand on opposite side of the template luckily shape long and hear each oth
Yakvenalex [24]

Answer:  120 ft

<u>Step-by-step explanation:</u>

The Ellipse equation is:   \dfrac{(x-h)^2}{a^2}-\dfrac{(y-k)^2}{b^2}=1       where

  • (h, k) is the center
  • "a" is the horizontal radius
  • "b" is the vertical radius
  • c is the distance from the center to the foci: |a² - b²| = c²

Given: horizontal diameter = 122  →  horizontal radius = 61 = a

          vertical diameter = 22  →  vertical radius = 11 = b

Foci (c):   61² - 11² = c²

            3721 - 121 = c²

                  3600 = c²

                    ±60 = c

Let (h, k) = (0, 0)

Then the foci are located at -60 and +60.

The distance between them is 60 + 60 = 120

3 0
4 years ago
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