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puteri [66]
2 years ago
13

Suppose a die is tossed 5 times. what is the probability of getting exactly 2 fours?

Mathematics
1 answer:
Tasya [4]2 years ago
7 0

Answer:

the probability of getting exactly 2 fours is 0.16

Step-by-step explanation:

The probability of obtaining a number that is four = ¹/₆

The probability of obtaining a non 4 number = 1 - ¹/₆ = ⁵/₆

The number of ways 2 fours can be arrange in five numbers = ⁵C₂ = 10 ways

If the die is tossed five times, the probability of the events is calculated as;

P = 10 x (¹/₆)² x (⁵/₆)³

P = 10 x (¹/₃₆) x  (¹²⁵/₂₁₆)

P = 10 x 0.02778 x 0.5787

P = 0.16

Therefore, the probability of getting exactly 2 fours is 0.16

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what is the equation, in slope- intercept form, of the line that contains the points (-3,4) and (5,7)
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Answer:

y = \frac{3}{8} x + \frac{41}{8}

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

To calculate the slope use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (- 3, 4) and (x₂, y₂ ) = (5, 7)

m = \frac{7-4}{5+3} = \frac{3}{8}, hence

y = \frac{3}{8} x + c ← is the partial equation

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using (5, 7 ), then

7 = \frac{15}{8} + c ⇒ c = 7 - \frac{15}{8} = \frac{41}{8}

y = \frac{3}{8} x + \frac{41}{8} ← equation in slope-intercept form


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