Help me find p.....

4. Suppose that Peculiar Purples and Outrageous Oranges are two different and unusual types of bacteria. Both types multiply thr

Viktor [21]

Answer:

Peculiar purples would be more abundant

Step-by-step explanation:

Given that eculiar Purples and Outrageous Oranges are two different and unusual types of bacteria. Both types multiply through a mechanism in which each single bacterial cell splits into four. Time taken for one split is 12 m for I one and 10 minutes for 2nd

The function representing would be

i) $P=P_0 (4)^{t/12}$ for I bacteria where t is no of minutes from start.

ii) $P=P_0 (4)^{t/10}$ for II bacteria where t is no of minutes from start. P0 is the initial count of bacteria.

a) Here P0 =3, time t = 60 minutes.

i) I bacteria P = $3(4)^{5} =3072$

ii) II bacteria P = $3(4)^{4} =768$

b) Since II is multiplying more we find that I type will be more abundant.

The difference in two hours would be

$3(4)^{10}- 3(4)^{8} =2949120$

c) i) $P=P_0 (4)^{t/12}$ for I bacteria where t is no of minutes from start.

ii) $P=P_0 (4)^{t/10}$ for II bacteria where t is no of minutes from start. P0 is the initial count of bacteria.

d) At time 36 minutes we have t = 36

Peculiar purples would be

$i) P=3 (4)^{36/12}=192$

The rate may not be constant for a longer time. Hence this may not be accurate.

e) when splits into 2, we get

$P=P_o (2^t)$ where P0 is initial and t = interval of time

7 0

3 years ago

Steph,andra,emily,and becca are planning a road trip from their hometown to san antonio

morpeh [17]

Answer:

a. Emily should begin her turn as the third driver at point (1, -0.5).

b. Emily's turn to drive end at point (-2.5, -3.75).

Step-by-step explanation:

Let assume that the group of girls travels from their hometown to San Antonio in a straight line. We know that each location is, respectively:

Hometown

$H(x,y) = (8,6)$

San Antonio

$T(x,y) = (-6,-7)$

Then, we can determine the end of each girl's turn to drive by the following vectorial expression based on the vectorial equation of the line:

Steph

$S(x,y) = H(x,y) + \frac{1}{4}\cdot [T(x,y)-H(x,y)]$ (1)

$S(x,y) = (8,6) + \frac{1}{4}\cdot [(-6,-7)-(8,6)]$

$S(x,y) = (8,6) +\frac{1}{4}\cdot (-14,-13)$

$S(x,y) = (4.5,2.75)$

Andra

$A(x,y) = H(x,y) + \frac{2}{4}\cdot [T(x,y)-H(x,y)]$ (2)

$A(x,y) = (8,6) + \frac{2}{4}\cdot [(-6,-7)-(8,6)]$

$A(x,y) = (8,6)+\frac{2}{4}\cdot (-14,-13)$

$A(x,y) =(1, -0.5)$

Emily

$E(x,y) = H(x,y) + \frac{3}{4}\cdot [T(x,y)-H(x,y)]$ (3)

$E(x,y) = (8,6) + \frac{3}{4}\cdot [(-6,-7)-(8,6)]$

$E(x,y) = (8,6)+\frac{3}{4}\cdot (-14,-13)$

$E(x,y) = (-2.5, -3.75)$

a. If the girls take turns driving and each girl drives the same distance, at what point should they stop from Emily to begin her turn as the third driver?

Emily's beginning point is the Andra's stop point, that is, $A(x,y) =(1, -0.5)$ .

Emily should begin her turn as the third driver at point (1, -0.5).

b. At what point does Emily's turn to drive end?

Emily's turn to drive end at point (-2.5, -3.75).

7 0

3 years ago

How do i add and subtract polynomials? (4v-6v)-(v-5v^3)+(5v^3+4)

Ksenya-84 [330]

Distribute and add like terms and you are good

alirghty

we can make it easier by simplifying what we can

(4v-6v)=-2v so

(-2v)-1(v-5v³)+(5v³+3)=
-2v-v+5v³+5v³+3=
10v³-3v+3

7 0

3 years ago

Given ΔMNO, find the measure of ∠LMN.

Novay_Z [31]

Answer:

104°

Step-by-step explanation:

If segments NO and NM are congruent, then angles NMO and NOM are congruent. So, their supplements, angles NML and NOP are congruent. That is ...

∠NML ≅ ∠NOP = 104°

∠NML = 104°

3 0

3 years ago