The expression as a sum or difference of logarithm is log(x^3) + log(√x + 1) - 2log(x - 2)
<h3>How to write the
expression as a sum or difference of
logarithm?</h3>
The expression is given as:
log [x^3 square root x 1/(x-2)^2
Rewrite properly as:
log [x^3 √x + 1/(x-2)^2]
Express the above expression as products and quotients
log [x^3 * √x + 1/(x-2)^2]
Apply the product and quotient of logarithm
log(x^3) + log(√x + 1) - log(x - 2)^2
Rewrite as:
log(x^3) + log(√x + 1) - 2log(x - 2)
Hence, the expression as a sum or difference of logarithm is log(x^3) + log(√x + 1) - 2log(x - 2)
Read more about logarithmic expression at
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Answer:
7x-9
Step-by-step explanation:
Answer:
70
Step-by-step explanation:
in parallelograms, the measure of reciprocal angles is equal to 180 because they are supplementary,
m<D = 110 so the measure of m<A which is reciprocal to m<D is equal to 70
Your answer is c 11 hope that helped
Answer:
24.46
ahh im so redfaced rn help lol XD
