The vector ab has a magnitude of 20 units and is parallel to the
vector 4i + 3j. Hence, The vector AB is 16i + 12j.
<h3>How to find the vector?</h3>
If we have given a vector v of initial point A and terminal point B
v = ai + bj
then the components form as;
AB = xi + yj
Here, xi and yj are the components of the vector.
Given;
The vector ab has a magnitude of 20 units and is parallel to the
vector 4i + 3j.
magnitude
Unit vector in direction of resultant = (4i + 3j) / 5
Vector of magnitude 20 unit in direction of the resultant
= 20 x (4i + 3j) / 5
= 4 x (4i + 3j)
= 16i + 12j
Hence, The vector AB is 16i + 12j.
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Answer:
First Question = 16 Second Question = 8
Step-by-step explanation:
First one
32+48=x(2+3)
80=5x
Divide each sides with 5 and you have x=16
Second one
32+48=4(x+12)
80=4x+48
subtract 48 from 48 and 80 and you have 32=4x.
Divide it with 4 both side and you have x=8
Answer:
5.6 quarts
Step-by-step explanation:
x + .15(8) = .50(8+x)
x + 1.2 = 4
.50x + 1.2 = 4
.50x = 2.8
x = 2.8/.50
x = 5.6 quarts
If there are 27 students in the class and they have to form as many groups of 4 as possible, you can calculate this using the following step:
27 / 4 = 6.75 = 6 3/4
Result: 27 students can form 6 groups of 4 students and 3 students have to form their own group.
