Answer:
1
Step-by-step explanation:
Question 1)
Volume of Tank A = Sum of volume of its two parts.
So,
Volume of Tank A = 24 + 96 = 120 cubic feet
Question 2)
Volume of Tank B and Tank A is the same. So, Volume of Tank B = 120 cubic feet
One section of Tank B = 45 cubic feet
So, volume of other section of tank B = 120 - 45 = 75 cubic feet
<span>68=-16t2+64t+8
16t2-64t+60=0
4t2-16t+15=0
(2t-5)(2t-3)=0
t=5/2 or 3/2
The object is at 68 feet after 3/2 secs, and returns to 68 feet after another second..</span>
So you wont forget what you wrote and it helps you to figure out the problem. I hope this helps.
3(12)/10(12) + 7(10)/12(10) = 36/120 + 70/120
==> 18/60 + 35/60 = 53/60
