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Goryan [66]
3 years ago
5

Identify the values of the variables. Give your answers in simplest radical form. PLEASE HELP!!

Mathematics
1 answer:
Talja [164]3 years ago
3 0

First question:

By definition of sine and cosine, we have

\sin30^\circ=\dfrac h{\sqrt5}\implies h=\dfrac{\sqrt5}2

\cos30^\circ=\dfrac g{\sqrt5}\implies g=\dfrac{\sqrt{15}}2

Second question:

By definition of tangent, we have

\tan60^\circ=\dfrac{5\sqrt2}x\implies x=\dfrac{5\sqrt2}{\sqrt3}=\dfrac{5\sqrt6}3

Then by Pythagoras' theorem,

(5\sqrt2)^2+x^2=y^2\implies y=\sqrt{(5\sqrt2)^2+\left(\dfrac{5\sqrt6}3\right)^2}=\sqrt{50+\dfrac{50}3}=\sqrt{\dfrac{200}3}=\dfrac{10\sqrt6}3

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FIND THE EXACT AREA PLEASE HELP ILL GIVE BRAINLIESTTTT
wolverine [178]

Check the picture below.

\textit{area of a circular ring}\\\\ A=\pi (R^2-r^2)~~ \begin{cases} r=\stackrel{smaller}{radius}\\ R=\stackrel{larger}{radius}\\[-0.5em] \hrulefill\\ r=2\\ R=3 \end{cases}\implies \begin{array}{llll} A=\pi (3^2-2^2)\implies A=5\pi \\\\\\ A\approx 15.71 \end{array}

5 0
2 years ago
Plz help will mark brainliest!
Troyanec [42]

Answer:

Measure of segment JL is 20 cm.

Step-by-step explanation:

By applying geometric mean theorem in the given right triangle,

\frac{JM}{KM}=\frac{KM}{ML}

(KM)^2=(LM)(ML)

8^2=(JM)(4)

JM=\frac{64}{4}

JM=16

Since, JL=JM+ML [By segment addition postulate]

JL=16+4

JL=20 cm

Therefore, measure of segment JL is 20 cm.

7 0
2 years ago
E. Lindsey sold stationery to her family and her mother's friends. She deposited the $125
IRISSAK [1]

Answer:

$134.71

Step-by-step explanation:

This is a simple interest question

A = P(1 + rt)

A = Amount after t months or years

P = Principal or amount saved

r = interest rate = 5.18% = 0.0518

t = time.in years = 18 months

= 1 year and 6 month

= 1.5 year

A = $125( 1 + 0.0518 × 1.5)

A = $125 ( 1 + 0.0777)

A = $125(1.0777)

A = $134.71

3 0
3 years ago
Does the point (-4, 2) lie inside or outside or on the circle x^2 + y^2 = 25?​<br>​
Lostsunrise [7]

Given equation of the Circle is ,

\sf\implies x^2 + y^2 = 25

And we need to tell that whether the point (-4,2) lies inside or outside the circle. On converting the equation into Standard form and determinimg the centre of the circle as ,

\sf\implies (x-0)^2 +( y-0)^2 = 5 ^2

Here we can say that ,

• Radius = 5 units

• Centre = (0,0)

Finding distance between the two points :-

\sf\implies Distance = \sqrt{ (0+4)^2+(2-0)^2} \\\\\sf\implies Distance = \sqrt{ 16 + 4 } \\\\\sf\implies Distance =\sqrt{20}\\\\\sf\implies\red{ Distance = 4.47 }

Here we can see that the distance of point from centre is less than the radius.

Hence the point lies within the circle .

3 0
2 years ago
Read 2 more answers
4x-35=9x<br><br>please help me i really need help
zhenek [66]
4x-35=9x
     -4x
-35=5x
divide by 5
x= -7
        
5 0
3 years ago
Read 2 more answers
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