Given:
Christopher scores 2 goals in a soccer game.
His goal total can vary from the average by 1 goal.
To find:
The absolute value equation can be used to calculate Christopher's maximum and minimum goals per game.
Solution:
Let Christopher scores x goals in a soccer game.
Then difference between actual goals and average goals is x-2.
His goal total can vary from the average by 1 goal.
Maximum number of goals = 2+1 = 3
Minimum number of goals = 2-1 = 1
It means, the difference between actual goals and average goals is either -1 and 1.
...(1)
...(2)
Using (1) and (2),we get

Therefore, the correct option is C.
Can’t get the answer what is m2?
f(x) = 5x²
f(10) = 5(10)² = 5(100) = 500
f'(x) = 10x
f'(10) = 10(10) = 100
Now, find the line that passes through (10, 500) and has a slope of 100
y - y₁ = m(x - x₁)
y - 500 = 100(x - 10)
y - 500 = 100x - 1000
y = 100x - 500
Answer:
18m
Step-by-step explanation:
Since the given traingles are similar
We get






Hence the distance across river is 18m