Answer:
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Step-by-step explanation:
The son’s age is unknown, so call it: X
The father’s age, four times older, so that means: 4*X= 4X (I use * for multiply)
After 16 years, we add 16 to both ages:
Son: X+16
Father: 4X+16, now, after 16yrs father’s age 2x older than son:
father→ 4X+16 = 2(X+16) = 2X+32 (father twice older than the son age)
4X +16= 2X+32 (after opening the brackets)
4X-2X= 32 - 16 ——-> we moved 2X to left, turned minus -, we moved 16 to the right turned minus -
2X = 16
X = 16/2 = 8
Son’s age is 8 yrs old
Father(Sunil) age is 4x8= 32
After 16 yrs, Father’s age twice older:
8+16=24 (son)
32+16= 48 (Father,Sunil, twice older than son)
