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viva [34]
3 years ago
5

At Luther's party she made three balloon poodles and two balloon giraffes Which used a total of 17 balloons for Jessica‘s party

she used 15 balloons to make one Balloon poodle and three balloon giraffes how many balloons does each animal require
Mathematics
1 answer:
olga55 [171]3 years ago
4 0

Answer:

The redaction does not explain the situation.  If we assume that 15 balloons were used to make one ballon poodle and three giraffes, then the answer would be 7,5 balloons for 1 poodle, and 2,5 balloons for a giraffe

Step-by-step explanation:

With 15 balloons we make 1 poodle and 3 giraffes.  This means that 7,5 balloons were used to make 1 poodle, and other 7,5 balloons were used to make 3 giraffes.

If we divide   7,5 balloons between 3, we obtain 2,5.  This means that with 2,5 balloons we make 1 giraffe

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An independent-measures study has one sample with n = 6 and a second sample with n = 8 to compare two experimental treatments. w
kifflom [539]

The df value for the t statistic for this study is 12.

To calculate the df value or degree of freedom we have to learn about test-statistic.

<h3>What is t statistics and how is it related to df(degree of freedom)?</h3>

In the field of statistics , T-statistic is the ratio of the estimated value of the perimeter to its standard error. Degree of freedom or df value denotes the number of data (from a sample) is used to calculate the estimate .

Importantly the degree of freedom is different from the sample space of an experiment.

The formula for calculating the df of a function is given by

df=N1+N2-2

So in the given question, N1=6 and N2=8

Substituting the values we get df=N1+N2-2=8+6-2=12 .

Therefore the value of the degree of freedom is 12.

To learn more about t-statistic and df values:

brainly.com/question/15236063

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3 0
2 years ago
If f(x)=2x-5 and g(x)=4x, find f(g(3)).<br> i’m sloww, 15 points
VARVARA [1.3K]

Answer:

  • 19

Step-by-step explanation:

<u>Given</u>

  • f(x)=2x-5
  • g(x)=4x,
  • f(g(3))= ?

<u>Solution:</u>

  • g(3) = 4*3 = 12
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Ella's home is 1,200 feet from the mall. How many yards is in 1,200?
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There are 400 yards between Ella's house and the mall. A yard has 3 feet
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Owen used these steps to solve the equation 4x+7=1+2(2x+3). Which choice describes the meaning of his result, 7=7?
ivanzaharov [21]

Answer:

Option D. All values of x make the equation true

Step-by-step explanation:

<u><em>The options of the question are</em></u>

a.The result is not correct because Step 2 has an error.

b.The solution is x=7.

c.No values of x make the equation true.

d.All values of x make the equation true

we have the equation

4x+7=1+2(2x+3)

solve for x

Apply distributive property right side

4x+7=1+4x+6

Combine like terms

4x+7=4x+7

subtract 4x both sides

7=7

The equation has infinity solutions

.All values of x make the equation true

6 0
3 years ago
Can someone help me with this? PLs i'm so confused!
barxatty [35]
1. E. sine\ A = \frac{a}{c} = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{5}{13}

2. L. cos\ A = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{12}{13}

3. tan\ A = \frac{a}{b} = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{5}{12}

4. Y. sin\ B = \frac{a}{c} = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{5}{13}

5. W. cos\ B = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{12}{13}

6. tan\ B = \frac{b}{a} = \frac{adjacent}{opposite} = \frac{AC}{BC} = \frac{12}{5} = 2\frac{2}{5}

7. sin\ A = \frac{a}{c} = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{1}{2}

8. W. cos\ A = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{\sqrt{3}}{2}

9. I. tan\ A = \frac{a}{b} = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{1}{\sqrt{3}} = \frac{1}{\sqrt{3}} * \frac{\sqrt{3}}{\sqrt{3}} = \frac{\sqrt{3}}{3}

10. sin\ B = \frac{a}{c} = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{1}{2}

11. E. cos\ B = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{\sqrt{3}}{1} = \sqrt{3}

12. I. tan\ B = \frac{a}{b} = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{1}{\sqrt{3}} = \frac{1}{\sqrt{3}} * \frac{\sqrt{3}}{\sqrt{3}} = \frac{\sqrt{3}}{3}

13. U. sin\ A = \frac{a}{c} = \frac{hypotenuse}{opposite} = \frac{BC}{AB} = \frac{12}{15} = \frac{4}{5}

14. I. cos\A = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{9}{15} = \frac{3}{5}

15. tan\ A = \frac{a}{b} = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{12}{9} = \frac{4}{3} = 1\frac{1}{3}

16. R. sin\ B = \frac{a}{c} = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{4}{\sqrt{65}} = \frac{4}{\sqrt{65}} * \frac{\sqrt{65}}{\sqrt{65}} = \frac{4\sqrt{65}}{65}

17. M. cos\ B = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{7}{4} = 1\frac{3}{4}

18. N. tan\ B = \frac{a}{b} = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{4}{7}

19. L. sin\ A = \frac{a}{c} = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{16}{34} = \frac{8}{17}

20. H. cos\ B = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \fac{AC}{AB} = \frac{30}{34} = \frac{15}{17}

21. tan\ B = \frac{a}{b} = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{16}{30} = \frac{8}{15}

22. O. sin\ A = \frac{a}{c} = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{1}{\sqrt{2}} = \frac{1}{\sqrt{2}} * \frac{\sqrt{2}}{\sqrt{2}} = \frac{\sqrt{2}}{2}

23. O. cos\ A = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{1}{\sqrt{2}} = \frac{1}{\sqrt{2}} * \frac{\sqrt{2}}{\sqrt{2}} = \frac{\sqrt{2}}{2}

24. N. tan\ A = \frac{a}{b} = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{1}{1} = 1
7 0
3 years ago
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