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3 years ago

HELP ASAP PLSSSS IM DESPERATE

Mathematics

2 answers:

Snezhnost [94]3 years ago

7 0

Answer:

C:A box plot titled Scores of Participants and labeled Scores uses a number line from 10 to 35 with primary markings and labels at 10, 15, 20, 25, 30, and 35. The box extends from 17 to 28 on the number line. A line in the box is at 21 The whiskers end at 12 and 29

Hope it helps

quester [9]3 years ago

4 0

Answer:

D.)

Step-by-step explanation:

Lowest point in the data is 12 and highest point in the data is 29 which is why the whiskers extend from 12 to 29. The line in the box is placed at 23 because this is the median. Lastly the box itself is extending from 17 to 28 because it represents the three quartiles. 17 being the first Quartile, 23 being the second Quartile (aka the median), and 28 being the third Quartile.

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A spinner has two equal sections, one green and one orange. The spinner is spun three times, resulting in the sample space S = {

Elina [12.6K]

Solution:

As given , Spinner has two equal Sections, one green and one Orange.

When the Spinner is Spun three times

Total Sample Space S= {GGG, GGO, GOG, OGG, GOO, OGO, OOG, OOO}

Random variable X is Selected, which represents number of times orange O' is spun, which is given by

X=0,1,2,3

Probability of an event = $\frac{\text{Total favorable outcome}}{\text{Total Possible outcome}}$

X=0, Probability of Orange(O), in G G G = $\frac{1}{8}$

X=1, Probability of Orange(O), in G G O , GOG,and O G G, 3 in total = $\frac{1}{8}$

X=2, Probability of Orange(O), in G O O , O GO,and O O G, 3 in total = $\frac{1}{8}$

X=3, Probability of Orange(O), in O O O, 1 in all= $\frac{1}{8}$

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3 years ago

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<img src="https://tex.z-dn.net/?f=%20-%205%20%3D%20a%20-%203" id="TexFormula1" title=" - 5 = a - 3" alt=" - 5 = a - 3" align="ab

Aloiza [94]

$~~-5=a-3\\\\\implies a =-5+3\\\\\implies a = -2$

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2 years ago

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Please help me answer this question

ratelena [41]

By the definition of the hyperbolic function tanh x, we have proven that $\frac{1-tanh \ x}{1 + tanh \ x}=e^{-2x}$

<h3>Hyperbolic functions & Proof of identities </h3>

By definition

$tanh \ x=\frac{e^{x} -e^{-x}}{e^{x} +e^{-x}}$

Then,

$\frac{1-tanh \ x}{1 + tanh \ x}=\frac{1-\frac{e^{x} -e^{-x}}{e^{x} +e^{-x}} }{1+ \frac{e^{x} -e^{-x}}{e^{x} +e^{-x}} }$

$=1-\frac{e^{x} -e^{-x}}{e^{x} +e^{-x}} \div (1+ \frac{e^{x} -e^{-x}}{e^{x} +e^{-x}} })$

$=\frac{e^{x} +e^{-x}-(e^{x} -e^{-x})}{e^{x} +e^{-x}} \div (\frac{e^{x} +e^{-x}+e^{x} -e^{-x}}{e^{x} +e^{-x}} })$

$=\frac{e^{x} +e^{-x}-e^{x} +e^{-x}}{e^{x} +e^{-x}} \div \frac{e^{x} +e^{-x}+e^{x} -e^{-x}}{e^{x} +e^{-x}} }$

$=\frac{e^{-x}+e^{-x}}{e^{x} +e^{-x}} \div \frac{e^{x} +e^{x} }{e^{x} +e^{-x}} }$

$=\frac{2e^{-x}}{e^{x} +e^{-x}} \div \frac{2e^{x} }{e^{x} +e^{-x}} }$

$=\frac{2e^{-x}}{e^{x} +e^{-x}} \times \frac{e^{x} +e^{-x}}{2e^{x}}$

$=\frac{2e^{-x}}{1} \times \frac{1}{2e^{x}}$

$=\frac{2e^{-x}}{2e^{x}}$

$=\frac{e^{-x}}{e^{x}}$
$=e^{-x} \times \frac{1}{e^{x}}$

$= e^{-x} \times e^{-x}$

$= e^{-x+-x}$

$= e^{-x-x}$

$= e^{-2x}$

Hence, we have proven that $\frac{1-tanh \ x}{1 + tanh \ x}=e^{-2x}$

Learn more on Proof of Identities here: brainly.com/question/2561079

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2 years ago

What is the value of angle 2x + 1 ? A.41 B.50 C.60 D.25<br><br>What is the value for x?

guajiro [1.7K]

Answer:

Step-by-step explanation:

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2x+1 = 7x-99

Subtract 2x from each side

2x+1-2x = 7x-2x-99

1 = 5x-99

Add 99 to each side

1+99 = 5x-99+99

100 = 5x

Divide each side by

100/5 = 5x/5

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The 2x+1 angle equals

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3 years ago

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mario62 [17]

Answer:

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4 years ago

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