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Licemer1 [7]
3 years ago
14

I NEED HELP ASAP Plot the image of point C under a dilation about point P with a scale factor of 2

Mathematics
1 answer:
Lostsunrise [7]3 years ago
7 0

the next point will be 5 units right from point C

sorry for being so late!! :))

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Function Notation
Westkost [7]
I checked all answers on Photomath.
Let me know if that’s helpful.

3 0
3 years ago
John needs 150 feet of rope to section off part of his barn. At a local hardware store he can buy a 30 yard spool for $24 or he
Sphinxa [80]

Answer:

30 yards for 24 vs 1 foot for 25 cents

so lets multiple the yards by 3 to see how many feet

90 feet = 30 yards

90 feet 24 dollars

now lets divide 90 by 24

3.75 so 3.75 per foot

so the second one is way better

Hope This Helps!!!

7 0
2 years ago
Read 2 more answers
Triangle QRS has been translated to create triangle Q'R'S'. RS= R'S' = 10 units, angles Q and Q' are both 90 degrees. Which post
RSB [31]

The <em><u>correct answer</u></em> is:

HL

Explanation:

These will both be right triangles, as angle Q and angle Q' are both 90 degrees.

Since Q and Q' are the right angles, this means that RS and R'S' are the hypotenuses of the two right triangles.

Since Q'R'S' was created by translating QRS, a corresponding leg of both triangles will be congruent; this gives us hypotenuse-leg, or HL.

6 0
4 years ago
Which of these changes in a pond environment is observable
LekaFEV [45]

Answer:

all of these are observable.

Step-by-step explanation:

you can look into how algae increase in the summer. You can visually see the water level is lower and you can feel the temperature of the water

6 0
3 years ago
Please help with these partial fractions!!!
VARVARA [1.3K]

a. Factorize the denominator:

\dfrac{x+14}{x^2-2x-8}=\dfrac{x+14}{(x-4)(x+2)}

Then we're looking for a,b such that

\dfrac{x+14}{x^2-2x-8}=\dfrac a{x-4}+\dfrac b{x+2}

\implies x+14=a(x+2)+b(x-4)

If x=4, then 18=6a\implies a=3; if x=-2, then 12=-6b\implies b=-2. So we have

\dfrac{x+14}{x^2-2x-8}=\dfrac3{x-4}-\dfrac2{x+2}

as required.

b. Same setup as in (a):

\dfrac{-3x^2+5x+6}{x^3+x^2}=\dfrac{-3x^2+5x+6}{x^2(x+1)}

We want to find a,b,c such that

\dfrac{-3x^2+5x+6}{x^2(x+1)}=\dfrac ax+\dfrac b{x^2}+\dfrac c{x+1}

Quick aside: for the second term, since the denominator has degree 2, we should be looking for another constant b' such that the numerator of the second term is b'x+b. We always want the polynomial in the numerator to have degree 1 less than the degree of the denominator. But we would end up determining b'=0 anyway.

\implies-3x^2+5x+6=ax(x+1)+b(x+1)+cx^2

If x=0, then b=6; if x=-1, then c=-2. Expanding everything on the right then gives

-3x^2+5x+6=ax^2+ax+bx+b+cx^2=(a-2)x^2+(a+6)x+6

which tells us a-2=-3 and a+6=5; in both cases, we get a=-1. Then

\dfrac{-3x^2+5x+6}{x^2(x+1)}=-\dfrac1x+\dfrac6{x^2}-\dfrac2{x+1}

as required.

5 0
4 years ago
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