All categories

3 years ago

I NEED HELP ASAP Plot the image of point C under a dilation about point P with a scale factor of 2

Mathematics

1 answer:

Lostsunrise [7]3 years ago

7 0

the next point will be 5 units right from point C

sorry for being so late!! :))

You might be interested in

Function Notation

Westkost [7]

I checked all answers on Photomath.
Let me know if that’s helpful.

3 0

3 years ago

John needs 150 feet of rope to section off part of his barn. At a local hardware store he can buy a 30 yard spool for $24 or he

Sphinxa [80]

Answer:

30 yards for 24 vs 1 foot for 25 cents

so lets multiple the yards by 3 to see how many feet

90 feet = 30 yards

90 feet 24 dollars

now lets divide 90 by 24

3.75 so 3.75 per foot

so the second one is way better

Hope This Helps!!!

7 0

2 years ago

Read 2 more answers

Triangle QRS has been translated to create triangle Q'R'S'. RS= R'S' = 10 units, angles Q and Q' are both 90 degrees. Which post

RSB [31]

The <em><u>correct answer</u></em> is:

Explanation:

These will both be right triangles, as angle Q and angle Q' are both 90 degrees.

Since Q and Q' are the right angles, this means that RS and R'S' are the hypotenuses of the two right triangles.

Since Q'R'S' was created by translating QRS, a corresponding leg of both triangles will be congruent; this gives us hypotenuse-leg, or HL.

6 0

4 years ago

Which of these changes in a pond environment is observable

LekaFEV [45]

Answer:

all of these are observable.

Step-by-step explanation:

you can look into how algae increase in the summer. You can visually see the water level is lower and you can feel the temperature of the water

6 0

3 years ago

Please help with these partial fractions!!!

VARVARA [1.3K]

a. Factorize the denominator:

$\dfrac{x+14}{x^2-2x-8}=\dfrac{x+14}{(x-4)(x+2)}$

Then we're looking for $a,b$ such that

$\dfrac{x+14}{x^2-2x-8}=\dfrac a{x-4}+\dfrac b{x+2}$

$\implies x+14=a(x+2)+b(x-4)$

If $x=4$ , then $18=6a\implies a=3$ ; if $x=-2$ , then $12=-6b\implies b=-2$ . So we have

$\dfrac{x+14}{x^2-2x-8}=\dfrac3{x-4}-\dfrac2{x+2}$

as required.

b. Same setup as in (a):

$\dfrac{-3x^2+5x+6}{x^3+x^2}=\dfrac{-3x^2+5x+6}{x^2(x+1)}$

We want to find $a,b,c$ such that

$\dfrac{-3x^2+5x+6}{x^2(x+1)}=\dfrac ax+\dfrac b{x^2}+\dfrac c{x+1}$

Quick aside: for the second term, since the denominator has degree 2, we should be looking for another constant $b'$ such that the numerator of the second term is $b'x+b$ . We always want the polynomial in the numerator to have degree 1 less than the degree of the denominator. But we would end up determining $b'=0$ anyway.