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3 years ago

The price of a scooter was ₹ 54,000 last year. It has increased by 20% this year. What is the price now? *

Mathematics

1 answer:

dlinn [17]3 years ago

5 0

I got 64,800 because you multiply 54,000 x 1.20 and that equals 64,800

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An amusement park charges and admission fee of 30 dollars for each person. Let C be the cost (in dollars) of admission for P peo

bogdanovich [222]

Answer:

Step-by-step explanation: B is the midpoint of AC, in other words it is the halfway point.

So A to B should be equal to B to C

Our expression is:

2x + 9 = 37

Subtract 9

2x = 28

Divide by 2

x = 14

5 0

3 years ago

4(2.1k-4)=6(3.4k-2) what does (K) equal?

LUCKY_DIMON [66]

Hey there.

4(2.1k - 4) = 6(3.4k - 2); apply the distributive property to remove the parenthesis.
8.4k - 16 = 20.4k - 12; Get the variable to one side, so subtract 8.4k.
-16 = 12k - 12; isolate the variable by adding 12.
-4 = 12k; divide by 12 to solve for our variable.
k = -1/3

I hope this helps!

6 0

4 years ago

Lily swims for 5 hours in stream that has a current of 1 mph. She leaves her dock, swims upstream for 2 miles and then swim back

antiseptic1488 [7]

Answer:

Swimming speed in still water is approximately 1.5 mph

Step-by-step explanation:

Given the speed of the current = 1 mph

distance she swims upstream =2 miles,

the total time = 5 hours.

She swam 2 miles upstream against the current and 2 miles back to the dock with the current. The formula that relates distance, time, and rate is $d = r t\ \ \ \ or \ \ \ t= \frac{d}{r}$

Let x be the speed in still water.

Then her speed with the current is x + 1, and

her speed against the current is x – 1.

Total time is equal to 2 miles with upstream and 2 miles downstream.

$\frac{2}{x+1}+\frac{2}{x-1}=5\\\\\frac{2(x-1)}{(x+1)(x-1)}+\frac{2(x+1)}{(x-1)(x+1)}=5\\\\\frac{2x-2}{(x^2-1)}+\frac{2x+2)}{(x^2-1)}=5\\\\\frac{2x-2+2x+2)}{(x^2-1)}=5\\\\4x=5(x^2-1)\\4x= 5x^2-5\\0= 5x^2-4x-5$

Now Using quadratic formula to solve above equation we get;

$x= \frac{-b \±\sqrt{b^2-4ac}} {2a}\\\\here \ \ a= 5,b=-4,c=-5\\\\x= \frac{-(-4) \±\sqrt{(-4)^2-4\times 5\times-5}} {2\times5}\\\\x=\frac{4 \±\sqrt{16+100}} {10}\\\\x=\frac{4 \±\sqrt{116}} {10}=x=\frac{4 \±2\sqrt{29}} {10}= x=\frac{2 \±\sqrt{29}} {5}\\ x \approx 1.5 \ or \ x = -0.7$

Since speed must be positive, Hence speed of still water is about 1.5 miles per hour.

3 0

3 years ago

Find the value of b.

Nesterboy [21]

Answer: $230^{\circ$

Step-by-step explanation:

For convenience, I labeled some points as shown in the attached picture.

Also, I assume $\overline{AB}$ and $\overline{BC}$ are tangents to the circle.

$\overline{BO} \cong \overline{BO}$ (reflexive property)
$\overline{AB} \cong \overline{BC}$ (tangents drawn from a common external point are congruent)
$\angle BAO \cong \angle BCO$ (right angles are congruent)