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3 years ago

Y = 3 - 5x solve for x

Mathematics

1 answer:

boyakko [2]3 years ago

4 0

Answer:

x = -1/5y + 3/5

Step-by-step explanation:

y = 3 - 5x

Subtract 3 from both sides;

y - 3 = -5x

Divide both sides by -5

-1/5y + 3/5 = x

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I need to collect 30 stickers. Each bag of crisps contains 3 stickers. How many bags will I need to buy?

soldier1979 [14.2K]

Hey there :)

Let p represent the number of bags to be bought

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3p = 30
↑ ↑
Number of stickers in a bad Number of stickers to be collected

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p = 10

We need to buy 10 bags of crisps to have 30 stickers

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3 years ago

Write the product 0.4x0.4x0.4 in exponential form

solmaris [256]

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3 years ago

83 random samples were selected from a normally distributed population and were found to have a mean of 32.1 and a standard devi

arlik [135]

Answer:

$\frac{(82)(2.4)^2}{104.139} \leq \sigma^2 \leq \frac{(82)(2.4)^2}{62.132}$

$4.525 \leq \sigma^2 \leq 7.602$

Now we just take square root on both sides of the interval and we got:

$2.127 \leq \sigma \leq 2.757$

Step-by-step explanation:

Information given

$\bar X=32.1$ represent the sample mean

$\mu$ population mean (variable of interest)

s=2.4 represent the sample standard deviation

n=83 represent the sample size

Confidence interval

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

The degrees of freedom given by:

$df=n-1=8-1=7$

The confidence level is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a table to find the critical values.

The excel commands would be: "=CHISQ.INV(0.05,82)" "=CHISQ.INV(0.95,82)". so for this case the critical values are:

$\chi^2_{\alpha/2}=104.139$

$\chi^2_{1- \alpha/2}=62.132$

The confidence interval is given by:

$\frac{(82)(2.4)^2}{104.139} \leq \sigma^2 \leq \frac{(82)(2.4)^2}{62.132}$

$4.525 \leq \sigma^2 \leq 7.602$

Now we just take square root on both sides of the interval and we got:

$2.127 \leq \sigma \leq 2.757$

5 0

3 years ago