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Alex787 [66]
3 years ago
10

Y = 3 - 5x solve for x

Mathematics
1 answer:
boyakko [2]3 years ago
4 0

Answer:

x = -1/5y + 3/5

Step-by-step explanation:

y = 3 - 5x

Subtract 3 from both sides;

y - 3 = -5x

Divide both sides by -5

-1/5y + 3/5 = x

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Quick please help!!!!
Westkost [7]

From the equation, we have

h=-20, k =21 , a^2=20^2, b^2=21^2

To find the vertex and focus, we have to use the following formula

Vertices =(h, k+-a) \\ Focii = (h,k+-c)

And

c = \sqrt{a^2 + b^2} = \sqrt{400+441} = 29

So, we have

Vertices=(-21,20+-20) \\ Focii=(-21, 20+-29)

Vertices =(-21,0),(-21,40) \\ focii=(-21,-9),(-21,49)

4 0
3 years ago
How does the volume of the cylinder compare to the volume of the cone
aniked [119]
A cylinder with the same radius and height as a cone will have 3 times the volume of the cone.

Vcone = (1/3)*π*r^2*h
Vcylinder = π*r^2*h
5 0
3 years ago
2x−7(y+1) when x=4, y =−3
Natasha_Volkova [10]

Answer:

22

Step-by-step explanation:

2x-7(y+1)

-7(-3+1)=14

2*4=8

8+14 is 22

5 0
3 years ago
Read 2 more answers
This is the new one! Please help I’m so lost
raketka [301]

Answer:

(a) (f o g)(x) =  x^2 - 15x + 54

(b) (g o f)(x) = x^2 + 3x - 9

(c) (f o f)(x) = x^4 + 6x^3 + 12x^2 + 9x

(d) (g o g)(x) = x - 18

Step-by-step explanation:

f(x) = x^2 + 3x

g(x) = x - 9

(a)

(f o g)(x) = f(g(x)) = (g(x))^2 + 3(g(x)) = (x - 9)^2 + 3(x - 9)

(f o g)(x) = x^2 - 18x + 81 + 3x - 27

(f o g)(x) = x^2 - 15x + 54

(b)

(g o f)(x) = g(f(x)) = f(x) - 9 = x^2 + 3x - 9

(c)

(f o f)(x) = f(f(x)) = (x^2 + 3x)^2 + 3(x^2 + 3x)

(f o f)(x) = x^4 + 6x^3 + 9x^2 + 3x^2 + 9x

(f o f)(x) = x^4 + 6x^3 + 12x^2 + 9x

(d)

(g o g)(x) = g(g(x)) = x - 9 - 9 = x - 18

3 0
4 years ago
Find the midpoint of segment AB A(-7,6) B(4,-2)
blagie [28]

Answer:4,05

Step-by-step explanation:

3 0
3 years ago
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