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3 years ago

9

The owner of an electronics store received a shipment of MP3 players at a cost of 64.25 each. If he sells the MP3 players for 99

.99 each, what is the percent of markup

1 answer:

Evgen [1.6K]3 years ago

4 0

It's about a 155.62645% markup. (99.99/64.25)=1.556264591439489, *100 to get percent.

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Chole is buying 2/3 pound of ham and 3/5 as many pounds of chesse as ham. Cheese cost $4.95 per pound, and ham cost 5/3 as much

slamgirl [31]

Answer:

$7.48.

Step-by-step explanation:

We have been given that Chole is buying 2/3 pound of ham and 3/5 as many pounds of cheese as ham.

First of all, we will find pounds of cheese bought by Chole by finding 3/5 of 2/3 as:

$\text{Pounds of cheese bought by Chole}=\frac{2}{3}\times \frac{3}{5}$

$\text{Pounds of cheese bought by Chole}=\frac{2}{5}$

We are told that cheese cost $4.95 per pound. Let us find cost of 2/5 pounds of cheese by multiplying 2/5 by $4.95 as:

$\text{Cost of cheese}=\$4.95\times \frac{2}{5}$

$\text{Cost of cheese}=\$1.98$

We are also told that ham cost 5/3 as much per pound as cheese. Let us find cost of per pound of ham by calculating 5/3 of $4.95 as:

$\text{Cost of per pound ham}=\$4.95\times \frac{5}{3}$

$\text{Cost of per pound ham}=\$8.25$

Cost of 2/3 pound of ham would be $8.25 times 2/3 as:

$\text{Cost of ham}=\$8.25\times \frac{2}{3}$

$\text{Cost of ham}=\$5.50$

$\text{Total cost of cheese and ham}=\$1.98+\$5.50$

$\text{Total cost of cheese and ham}=\$7.48$

Therefore, Chole will pay $7.48 for the cheese and ham.

7 0

3 years ago

In a large local high school, 19% of freshmen have had their wisdom teeth removed and 24% of seniors have had their wisdom teeth

soldi70 [24.7K]

Answer:

0.2643 = 26.43% probability that the proportion of freshmen who have had their wisdom teeth removed is greater than the proportion of seniors.

Step-by-step explanation:

To solve this question, we need to understand the normal distribution, the central limit theorem, and subtraction of normal variables.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}}$

Subtraction of normal variables:

When we subtract normal variables, the mean of the subtraction will be the subtraction of the means, while the standard deviation will be the square root of the sum of the variances.

In a large local high school, 19% of freshmen have had their wisdom teeth removed. Sample of 60 freshmen:

So, by the central limit theorem:

$\mu_f = 0.19, s_f = \sqrt{\frac{0.19*0.81}{60}} = 0.0506$

24% of seniors have had their wisdom teeth removed. Sample of 50 seniors.

So, by the central limit theorem:

$\mu_s = 0.24, s_s = \sqrt{\frac{0.24*0.76}{50}} = 0.0604$

What is the probability that the proportion of freshmen who have had their wisdom teeth removed is greater than the proportion of seniors?

This is the probability that the subtraction of the proportion of freshmen by the proportion of seniors is larger than 0. For this distribution, we have that:

$\mu = \mu_f - \mu_s = 0.19 - 0.24 = -0.05$

$s = \sqrt{s_f^2 + s_s^2} = \sqrt{0.0506^2 + 0.0604^2} = 0.0788$

This probability is 1 subtracted by the pvalue of Z when X = 0. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{0 - (-0.05)}{0.0788}$

$Z = 0.63$

$Z = 0.63$ has a pvalue of 0.7357

1 - 0.7357 = 0.2643

0.2643 = 26.43% probability that the proportion of freshmen who have had their wisdom teeth removed is greater than the proportion of seniors.

3 0

3 years ago

An equation of the line with a slope of 2 and y-intercept of 9

7nadin3 [17]

Answer:

y = 2x + 9

General Formulas and Concepts:

<u>Algebra I</u>

Slope-Intercept Form: y = mx + b

m - slope

b - y-intercept

Step-by-step explanation:

<u>Step 1: Define</u>

Slope <em>m</em> = 2

y-intercept <em>b</em> = 9

<u>Step 2: Write linear equation</u>

Slope-Intercept Form: y = 2x + 9

3 0

3 years ago

What is the value of the expression below when x=1?<br> 4x² + 5

SpyIntel [72]

Answer:

its 9

Step-by-step explanation:

bec 1 square is 1 and 4 +5 is 9

3 0

3 years ago

Read 2 more answers

What are the numbers of symmetries for this figure? Enter your answers in the boxes. Number of rotational symmetries: Number of

Ann [662]

Answer:

??? and 0

Step-by-step explanation:

Ok I don't know about the first one but all I know is that it has 0 reflectional symmetries. Apologies for that but I wish you luck on your work and hopefully this somewhat helps a bit. ;-D

3 0

3 years ago