All categories

3 years ago

A fish tank holds approximately how much water?

Mathematics

1 answer:

Bas_tet [7]3 years ago

3 0

Answer:

Fish tanks come in all different sizes. I can't answer unless you tell me the dimensions (Length, width, height)

Step-by-step explanation:

You might be interested in

Given the equations f(x) = x + 4 and d (x) = 2x + 5, find: f (1) + d (2)

Lina20 [59]

1 = x + 4
3 = x

2 = 2x + 5
3 = 2x
3/2= x

3 0

3 years ago

Equation of a line with slope 1/5 through the point (-5, -4)

Harrizon [31]

9514 1404 393

Answer:

y +4 = (1/5)(x +5)

Step-by-step explanation:

The point-slope form of the equation of a line is useful when you have a given point and slope.

y -k = m(x -h) . . . . . . line with slope m through point (h, k)

Filling in the given values, this is ...

y +4 = 1/5(x +5)

7 0

3 years ago

A square tile has a width of 1/4 foot.How many tiles will fit end-to-end along a 4- foot tiles

Jobisdone [24]

16 tiles would fit.

6 0

4 years ago

For the figures below, assume they are made of semicircles, quarter circles and squares. For each shape, find the area and perim

ICE Princess25 [194]

Answer:

Part a) The area of the figure is $\frac{9}{2}(4+\pi )\ cm^{2}$

Part b) The perimeter of the figure is $3(2+2\sqrt{2}+ \pi)\ cm$

Step-by-step explanation:

Step 1

Find the area of the figure

In this problem we have that

The figure ABC is the half of a square and the other figure is a semicircle

<u>Find the area of the figure ABC</u>

we have

$AB=6\ cm, BC=6\ cm$

The area of the half square ABC is equal to find the area of triangle ABC

$A1=\frac{1}{2}*6*6=18\ cm^{2}$

<u>Find the area of the semicircle</u>

The area of the semicircle is equal to

$A2=\pi r^{2}/2$

we have that

$r=6/2=3\ cm$

substitute

$A2=\pi (3)^{2}/2$

$A2=(9/2) \pi\ cm^{2}$

The area of the figure is equal to

$18\ cm^{2}+(9/2) \pi\ cm^{2}= \frac{9}{2}(4+\pi )\ cm^{2}$

Step 2

Find the perimeter of the figure

The perimeter of the figure is equal to

$P=AB+AC+length\ CB$

we have

$AB=6\ cm$

Applying Pythagoras theorem

$AC=\sqrt{6^{2}+6^{2}}\\AC=6\sqrt{2}\ cm$

Remember that

the circumference of a semicircle is equal to

$C=\frac{1}{2}2\pi r=\pi r$

$r=6/2=3\ cm$

$C=\pi(3)$

$C=3 \pi\ cm$

The perimeter of the figure is equal to

$P=6\ cm+6\sqrt{2}\ cm+3 \pi\ cm$

Simplify

$P=3(2+2\sqrt{2}+ \pi)\ cm$

5 0

3 years ago

Guys I need the answers to number 16

Umnica [9.8K]

#16: Let's clear the fraction on the way to solving this inequality for x. By mult. the given inequality by 2, we'll get -2 (is greater than) x+4. We want x to be positive. So, leave it where it is. Subtract 4 from both sides of this inequality. We end up with -6 (is greater than) x, which is the same thing as x (is less than) -6. What would the graph of that simple inequality look like?

Graph it. (Hint: The graph is a straight dashed line, and you must shade one side of it, but not the other side.

6 0

4 years ago