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3 years ago

How is everyone's day going? Mine is okay can u help me on this question?

Mathematics

2 answers:

IrinaVladis [17]3 years ago

8 0

Answer:

x = 2 and y = 7

Step-by-step explanation:

We are given two equations:

1. 8x + y = 23

2. −10x - y = −27

By adding both equations with each other we get:

(1.+2.) -2x = -4

Which can be reduced to:

(1.+2. : (-2)) x = 2

We can insert x in Equation 1. (or 2) and get:

8*2 + y = 23

16 + y = 23 [-16 on both sides]

y = 7

Resulting in x = 2 and y = 7 as a possible solution for this system.

ludmilkaskok [199]3 years ago

4 0

Answer:

Step-by-step explanation:

8x + y = 23

-10x - y = -27

-2x = -4

x = 2

8(2) + y = 23

16 + y = 23

y = 7

(2, 7)

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A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each. If 20000 tickets are sold at 2

Shalnov [3]

Answer:

The expected winnings for a person buying 1 ticket is -0.2.

Step-by-step explanation:

Given : A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each. If 20000 tickets are sold at 25 cents each, find the expected winnings for a person buying 1 ticket.

To find : What are the expected winnings?

Solution :

There are one first prize, 2 second prize and 20 third prizes.

Probability of getting first prize is $\frac{1}{20000}$

Probability of getting second prize is $\frac{2}{20000}$

Probability of getting third prize is $\frac{20}{20000}$

A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each.

So, The value of prizes is

$\frac{1}{20000}\times 1000+\frac{2}{20000}\times 300+\frac{20}{20000}\times 10$

If 20000 tickets are sold at 25 cents each i.e. $0.25.

Remaining tickets = 20000-1-2-20=19977

Probability of getting remaining tickets is $\frac{19977}{20000}$

The expected value is

$E=\frac{1}{20000}\times 1000+\frac{2}{20000}\times 300+\frac{20}{20000}\times 10-\frac{19977}{20000}\times 0.25$

$E=\frac{1000+600+200-4994.25}{20000}$

$E=\frac{-3194.25}{20000}$

$E=-0.159$

Therefore, The expected winnings for a person buying 1 ticket is -0.2.

3 0

3 years ago

What are the constant terms in the expression? 8m−5n+2+m−148m−5n+2+m−14 Drag and drop the constant terms into the box.

krek1111 [17]

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3 years ago

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4 years ago

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svetlana [45]

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3 years ago

4x = 37 311 127 77 328

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3 years ago