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kenny6666 [7]
3 years ago
12

How is everyone's day going? Mine is okay can u help me on this question?

Mathematics
2 answers:
IrinaVladis [17]3 years ago
8 0

Answer:

x = 2 and y = 7

Step-by-step explanation:

We are given two equations:

1.      8x + y = 23

2. −10x  - y = −27

By adding both equations with each other we get:

(1.+2.) -2x = -4

Which can be reduced to:

(1.+2. : (-2)) x = 2

We can insert x in Equation 1. (or 2) and get:

8*2 + y = 23

16 + y = 23         [-16 on both sides]

y = 7

Resulting in x = 2 and y = 7 as a possible solution for this system.

ludmilkaskok [199]3 years ago
4 0

Answer:

Step-by-step explanation:

8x + y = 23

-10x - y = -27

-2x = -4

x = 2

8(2) + y = 23

16 + y = 23

y = 7

(2, 7)

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Find the future value of an annuity due of $7,000 paid at the beginning of each 6-month period for 8 years if the interest rate
Oliga [24]

Answer: Im not sure but i think its 120,960

Step-by-step explanation: i know that there is 2 of the 6-month periods in a year and multiplied that by 8 and got 16. Then i did 7000x.08=560 and then i added that to 7000 and got 7560. FInally i multiplied that by 16 and got 120,960.

4 0
3 years ago
Using traditional methods it takes 92 hours to receive an advanced flying license. A new training technique using Computer Aided
DanielleElmas [232]

Answer:

The value of the test statistic is z = 1.39.

The p-value of the test is 0.0823 > 0.05, which means that there is not evidence at the 0.05 level that the technique lengthens the training time.

Step-by-step explanation:

Using traditional methods it takes 92 hours to receive an advanced flying license.

This means that at the null hypothesis, it is tested if the mean is of 92, that is:

H_0: \mu = 92

Test if there is evidence that the technique lengthens the training time

At the alternative hypothesis, it is tested if the mean is more than 92, that is:

H_1: \mu > 92

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

92 is tested at the null hypothesis:

This means that \mu = 92

A researcher used the technique on 70 students and observed that they had a mean of 93 hours. Assume the population variance is known to be 36.

This means that n = 70, X = 93, \sigma = \sqrt{36} = 6

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{93 - 92}{\frac{6}{\sqrt{70}}}

z = 1.39

The value of the test statistic is z = 1.39.

P-value of the test and decision:

The p-value of the test is the probability of finding a sample mean above 93, which is 1 subtracted by the p-value of z = 1.39.

Looking at the z-table, z = 1.39 has a p-value of 0.9177.

1 - 0.9177 = 0.0823.

The p-value of the test is 0.0823 > 0.05, which means that there is not evidence at the 0.05 level that the technique lengthens the training time.

8 0
3 years ago
Find the determinant of this matrix:
Bogdan [553]

Answer:

40

Step-by-step explanation:

\left[\begin{array}{ccc}a&b\\c&d\end{array}\right] = ad-bc

4 0
2 years ago
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gogolik [260]

Answer:

B is correct.

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2 years ago
Rearrange to make x the subject
Zolol [24]
Answer
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Step by step explanation
t = bx/3
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