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3 years ago

Redo! one geo question thank youu

Mathematics

1 answer:

svetlana [45]3 years ago

3 0

Answer is in the pic above. Theorems used:

Exterior angle theorem

Inscribed angle theorem.

$\angle EBF=32.5°$

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Jeans (x) cost $10, shirts (y) cost $5, and socks (z) cost $3. On Wednesday a store sold a total of 150 items for a total of $90

Virty [35]

Answer:

the answer is 900

Step-by-step explanation:

the 900 will not be necessary

7 0

3 years ago

Need help ASAP I really need help reviewing this!! Making sure if I have the correct answer !!!

kow [346]

Answer:

1) 5

2) 7

3) Mary

Step-by-step explanation:

1) 20/4 = 5 shots

20 shots = 4 minutes

10 shots = 2 minutes

5 shots = 1 minute

2) 42/6 = 7 shots

42 shots = 6 minutes

21 shots = 3 minutes

21 shots divided by 3 minutes equals 7 shots

3) Mary had 7 shots while John only shot 5.

4 0

3 years ago

Which quadratic function has an axis of symmetry of x = 3?

Leona [35]

Answer:

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3 years ago

Commom denominator of 9 15

Rom4ik [11]

One common denominator is 45

6 0

3 years ago

Assume y≠60 which expression is equivalent to (7sqrtx2)/(5sqrty3)

Drupady [299]

Answer:

The equivalent will be:

$\frac{\sqrt[7]{x^2}}{\sqrt[5]{y^3}}=\left(\:x^{\frac{2}{7}}\right)\left(y^{-\frac{3}{5}}\right)$

Therefore, option 'a' is true.

Step-by-step explanation:

Given the expression

$\frac{\sqrt[7]{x^2}}{\sqrt[5]{y^3}}$

Let us solve the expression step by step to get the equivalent

$\frac{\sqrt[7]{x^2}}{\sqrt[5]{y^3}}$

$\sqrt[7]{x^2}=\left(x^2\right)^{\frac{1}{7}}$ ∵ $\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a}=a^{\frac{1}{n}}$

$\mathrm{Apply\:exponent\:rule:\:}\left(a^b\right)^c=a^{bc},\:\quad \mathrm{\:assuming\:}a\ge 0$

$=x^{2\cdot \frac{1}{7}}$

$=x^{\frac{2}{7}}$

also

$\sqrt[5]{y^3}=\left(y^3\right)^{\frac{1}{5}}$ ∵ $\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a}=a^{\frac{1}{n}}$

$\mathrm{Apply\:exponent\:rule:\:}\left(a^b\right)^c=a^{bc},\:\quad \mathrm{\:assuming\:}a\ge 0$

$=y^{3\cdot \frac{1}{5}}$

$=y^{\frac{3}{5}}$

so the expression becomes

$\frac{x^{\frac{2}{7}}}{y^{\frac{3}{5}}}$

$\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}$

$=\left(\:x^{\frac{2}{7}}\right)\left(y^{-\frac{3}{5}}\right)$ ∵ $\:\frac{1}{y^{\frac{3}{5}}}=y^{-\frac{3}{5}}$

Thus, the equivalent will be:

$\frac{\sqrt[7]{x^2}}{\sqrt[5]{y^3}}=\left(\:x^{\frac{2}{7}}\right)\left(y^{-\frac{3}{5}}\right)$

Therefore, option 'a' is true.

5 0

3 years ago