This shows that about 7 and 3 pounds of each chocolate were included in the mixture.
Let the number of pounds of both chocolates be x and y.
If Enrico sold a 10-pound box of assorted chocolates, hence;
x + y = 10 ................. 1
If some of the chocolates in the box sold for $1.75 per pound and some sold for $2.00 per pound with mixture sold for $1.90 per pound, then:
1.75x + 2x = 1.90 ................ 2
Solve equations 1 and 2 simultaneously.
x + y = 10 ................. 1 * 20
17.5x + 20x = 19 ................ 2 * 1
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20x + 20y = 200
17.5x + 20x = 19
Subtract
20x - 17.5x = 200 - 19
2.5x = 181x = 7.24
Substitute 7.24 into 1
x + y = 10
y = 10 - 7.24
x = 2.76
This shows that about 7 and 3 pounds of each chocolate were included in the mixture.
Learn more here: brainly.com/question/15165519
It’s d, 1 - t
t + 3 - 2 - 2t
we can rearrange it as
t - 2t + 3 - 2
-t + 1 is the same as 1 - t
Let c = hypotenuse and a = leg 1 and b = leg 2. If c² > a² + b², then it is obtuse. If it is less, then it is acute. I hope it helps.
I think the answer is 1.06666666667
Answer:
5
Step-by-step explanation:
The squares with 2, 6, 4, 3 will be all the left, front, right, back sides. The 1 and 5 will flap up/down to be the top and bottom. So 1 and 5 will be opposite from each other.
