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Andrei [34K]
3 years ago
13

Carrie needs to take a cab uptown and only has y dollars. The cab company charges a flat fee of $2.25 plus $0.55 per mile.

Mathematics
2 answers:
Gwar [14]3 years ago
5 0
Answer:
Maximum distance covered by Carrie = 22.8 miles
Step-by-step explanation:
The cab company charges a flat fee of $2.25 plus $0.55 per mile.
Amount of money Carrie has = $y
Let the number of miles traveled in $y = x miles
If Carrie finds a cab charging same fee and $0.45 per mile,
y ≤ 2.25 + 0.45x
y - 2.25 ≤ 0.45x

Therefore, inequality representing the maximum distance covered by Carrie,

If, y = $12.52

x ≤ 22.8 miles
Therefore, Carrie will be able to travel the maximum distance = 22.8 miles.
baherus [9]3 years ago
3 0

Answer:

27.8 miles

Step-by-step explanation:

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Read 2 more answers
The prices of commodities X,Y,Z are respectively x, y, z, rupees per unit. Mr. A purchases 4 units of Z and sells 3 units of X a
liubo4ka [24]

Answer:

(x,y,z)=(1477, 1464, 1437)

Step-by-step explanation:

Consider the selling of the units positive earning and the purchasing of the units negative earning.

<h3>Case-1:</h3>
  • Mr. A purchases 4 units of Z and sells 3 units of X and 5 units of Y
  • Mr.A earns Rs6000

So, the equation would be

3x  +  5y - 4z = 6000

<h3>Case-2:</h3>
  • Mr. B purchases 3 units of Y and sells 2 units of X and 1 units of Z
  • Mr B neither lose nor gain meaning he has made 0₹

hence,

2x   - 3y  +  z = 0

<h3>Case-3:</h3>
  • Mr. C purchases 1 units of X and sells 4 units of Y and 6 units of Z
  • Mr.C earns 13000₹

therefore,

- x    + 4y  +  6z = 13000

Thus our system of equations is

\begin{cases}3x  +  5y - 4z = 6000\\2x   - 3y  +  z = 0\\ - x    + 4y  +  6z = 13000\end{cases}

<u>Solving </u><u>the </u><u>system </u><u>of </u><u>equations</u><u>:</u>

we will consider elimination method to solve the system of equations. To do so ,separate the equation in two parts which yields:

\begin{cases}3x  +  5y - 4z = 6000\\2x   - 3y  +  z = 0\end{cases}\\\begin{cases}2x   - 3y  +  z = 0\\ - x    + 4y  +  6z = 13000\end{cases}

Now solve the equation accordingly:

\implies\begin{cases}11x-7y=6000\\-13x+22y=13000\end{cases}

Solving the equation for x and y yields:

\implies\begin{cases}x= \dfrac{223000}{151}\\\\y= \dfrac{221000}{151}\end{cases}

plug in the value of x and y into 2x - 3y + z = 0 and simplify to get z. hence,

\implies z= \dfrac{217000}{151}

Therefore,the prices of commodities X,Y,Z are respectively approximately 1477, 1464, 1437

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