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3 years ago

Which step would come first in the order of operations?

Mathematics

1 answer:

MrMuchimi3 years ago

5 0

Parentheses then exponents then multiply then divided then add then substract

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Find the measure of the numbered angles for the parallelogram in question one!!!

vodka [1.7K]

1) 70
2) 110
3) 70

because 110 is equivalent to angle 2. angle 1 and 3 are also equivalent so you add 110 + 110 which equals 220 and subtract 360-220 which equals 140 and divide by 2 to get angles 1 and 3.

7 0

3 years ago

3.27x+1.28y+1.83x−2.77y

Firdavs [7]

Answer:

5.1x - 1.49y

Step-by-step explanation:

We need to add or substract like terms.

like terms are the terms that have the same variable, in this case:

3.27x and 1.83x are like terms, and adding them we get:

3.27x + 1.83x = 5.1x (you add only the coefficients and the x stays the same)

we do the same for the terms with 'y':

1.28y and −2.77y are like terms, but in this case we must substract because of the − sign:

1.28y −2.77y = -1.49y

the final answer is the conjunction of the two results that we obtained:

5.1x - 1.49y

8 0

3 years ago

In a study of computer use, 1000 randomly selected Canadian Internet users were asked how much time they spend using the Interne

Dvinal [7]

Answer:

b. Do not reject H0. We do not have convincing evidence that the mean weekly time spent using the Internet by Canadians is greater than 12.7 hours.

Step-by-step explanation:

Given that in a study of computer use, 1000 randomly selected Canadian Internet users were asked how much time they spend using the Internet in a typical week. The mean of the sample observations was 12.9 hours.

$H_0: \bar x =12.7\\H_a: \bar x >12,7$

(Right tailed test at 5% level)

Mean difference = 0.2

Std error = $\frac{6}{\sqrt{1000} } \\=0.1897$

Z statistic = 1.0540

p value = 0.145941

since p >alpha we do not reject H0.

b. Do not reject H0. We do not have convincing evidence that the mean weekly time spent using the Internet by Canadians is greater than 12.7 hours.

5 0

3 years ago

www.g The physical plant at the main campus of a large state university recieves daily requests to replace fluorescent lightbulb

damaskus [11]

Answer:

$z=\frac{24-40}{8}=-2$

$z=\frac{40-40}{8}=0$

And then the percentage between 24 and 40 would be $\frac{95}{2}= 47.5 \%$

Step-by-step explanation:

For this problem we have the following parameters given:

$\mu = 40, \sigma =8$

And for this case we want to find the percentage of lightbulb replacement requests numbering between 24 and 40.

From the empirical rule we know that we have 68% of the values within one deviation from the mean, 95% of the values within 2 deviations and 99.7% within 3 deviations.

We can find the number of deviations from themean for the limits with the z score formula we got:

$z=\frac{X-\mu}{\sigma}$