All categories

2 years ago

Plz help marking brainiest answers!!!

Mathematics

1 answer:

Nady [450]2 years ago

8 0

2(13) = 26
-3(6) = -18
26 - 18
=8
so the answer is A

You might be interested in

Simplify the ratio of 15:24

Anettt [7]

15÷3 and 24÷3

= 5:8
hop u found this helpful

3 0

2 years ago

Read 2 more answers

What are the x- and y-intercepts for the graph of 5x – 2y = 20?

Elza [17]

Answer:

x-intercept = 4

y-intercept = −10

Step-by-step explanation:

x-intercept: Plug 0 in for $y$ to get this:

$5x = 20 \\ \\ 4 = x$

y-intercept: Plug 0 in for $x$ to get this:

$-2y = 20 \\ \\ -10 = y$

I am joyous to assist you anytime.

3 0

2 years ago

Read 2 more answers

If two lines are perpendicular describe the relationship between their slopes

Aloiza [94]

Perpendicular lines have slopes that are negative reciprocals. example: line a has a slope of 2/3, line b has a slope if -3/2 if they are perpendicular.

7 0

2 years ago

Trigonometric functions

givi [52]

Answer:

udg7838jsj

Step-by-step explanation:

888888888888 9283

3 0

2 years ago

Read 2 more answers

Determine the zeroes of the polynomial

Anna71 [15]

Answer:

3,7/6

Step-by-step explanation:

$(\sqrt{x^2-4x+3} )+(\sqrt{x^{2} -9} )-(\sqrt{4x^2-14x+6} )\\=(\sqrt{x^2-x-3x+3} )+(\sqrt{(x^2-3^2})-(\sqrt{4x^2-2x-12x+6})\\ =(\sqrt{x(x-1)-3(x-1)} )+\sqrt{(x+3)(x-3)}-\sqrt{2x(2x-1)-6(2x-1)} \\=\sqrt{(x-1)(x-3)}+\sqrt{(x+3)(x-3)} -\sqrt{2(2x-1)(x-3)} \\=\sqrt{x-3} (\sqrt{x-1} +\sqrt{x+3} -\sqrt{2(2x-1)} )\\$

$\sqrt{x-3} =0~gives~x=3\\or~\sqrt{x-1} +\sqrt{x+3} -\sqrt{2(2x-1)} =0\\or~ \sqrt{x-1} +\sqrt{x+3} =\sqrt{2(2x-1)} \\squaring\\x-1+x+3+2\sqrt{x-1} \sqrt{x+3} =2(2x-1)\\2x+2+2\sqrt{(x-1)(x+3)} =4x-2\\2\sqrt{x^2-x+3x-3} =2x-4\\\sqrt{x^2+2x-3} =x-2\\again ~squaring\\x^2+2x-3=x^2-4x+4\\\\2x+4x=4+3\\6x=7\\x=\frac{7}{6}$

8 0

2 years ago