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MrRissso [65]
3 years ago
8

Opjopdjawopdjopajjow

SAT
2 answers:
Basile [38]3 years ago
3 0

\huge \underbrace \mathfrak \red {Answer }

bakqoapnzhuxjqjllkdohzhwbskq

Mumz [18]3 years ago
3 0

Answer:

Vtrggrfrrgfhfyrrtgytrrh? Rrgrbygre?

Explanation:

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Select the correct answer. what is the value of this limit? a. b. c. d. e.
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The value of the limit expression \lim_{x \to 3} \sqrt{x^2 + 7} + 5 is 9, and it means that the function approaches 9, as x approaches 3.

<h3>How to evaluate the limit?</h3>

The limit expression is given as:

\lim_{x \to 3} \sqrt{x^2 + 7} + 5

This means that we determine the value of the function as x approaches 3.

So, we have:

Limit = √(3^2 + 7) + 5

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Limit = √(9 + 7) + 5

Evaluate the sum

Limit = √16 + 5

Evaluate the square root

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Limit = 9

Hence, the value of the limit \lim_{x \to 3} \sqrt{x^2 + 7} + 5 is 9

Read more about limits at:

brainly.com/question/14143957

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Question 22 of 25
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