Question

ANSWER THESE 2 QUESTIONS FOR 100 FLIPPING POINTS :DDDD

Answer 1

Answer:

$\displaystyle 3) \boxed{ \rm {43.5 \: cm}^{2} }$

$\displaystyle 4)\rm \boxed{112 {cm}^{2} }$

Step-by-step explanation:

Question-1:

we are given a triangle and we want to figure out the area of it Since we are given the base and the height we can consider the following formula

$\displaystyle \frac{1}{2} bh$

from the triangle we can assume base and height as 14.5 and 8 respectively Thus substitute:

$\displaystyle \frac{1}{2} (14.5cm)(6cm)$

reduce fraction:

$\displaystyle (14.5cm)(3cm)$

simplify multiplication:

$\displaystyle \boxed{ \rm {43.5 \: cm}^{2} }$

Question-2:

our given shape is trapezoid

therefore recall that,

$\displaystyle A _{ \text{trapezoid}} = \frac{a + b}{2} h$

from the shape we define that

• $a = 9$
• $b = 19$
• $h = 8$

now substitute:

$\displaystyle \rm A _{ \text{trapezoid}} = \frac{9cm + 19cm}{2} (8cm)$

reduce fraction:

$\displaystyle \rm A _{ \text{trapezoid}} = (9cm + 19cm)(4cm)$

simplify addition:

$\displaystyle \rm A _{ \text{trapezoid}} = (28cm)(4cm)$

simplify multiplication:

$\displaystyle \rm A _{ \text{trapezoid}} = \boxed{112 {cm}^{2} }$

Answer 2

Answer:

43.5 cm² and 112 cm²

Step-by-step explanation:

Here the instructions aren't given what to do. So I am finding the area of the ∆s .

Area of first ∆ :-

• A = 1/2 * b * h
• A = 1/2 * 14.5 cm * 6cm
• A = 3 × 14.5 cm²
• A = 43.5 cm²

Area of second ∆ :-

• A = 1/2 * ( sum of || sides) * h
• A = 1/2 * ( 9 cm + 19cm) * 8cm
• A = 4cm * 28cm
• A = 112 cm²