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MissTica
3 years ago
11

ANSWER THESE 2 QUESTIONS FOR 100 FLIPPING POINTS :DDDD

Mathematics
2 answers:
Shtirlitz [24]3 years ago
4 0

Answer:

\displaystyle 3) \boxed{ \rm {43.5 \: cm}^{2} }

\displaystyle   4)\rm  \boxed{112 {cm}^{2} }

Step-by-step explanation:

<h3>Question-1:</h3>

we are given a triangle and we want to figure out the area of it Since we are given the base and the height we can consider the following formula

\displaystyle  \frac{1}{2}  bh

from the triangle we can assume base and height as 14.5 and 8 respectively Thus substitute:

\displaystyle  \frac{1}{2}  (14.5cm)(6cm)

reduce fraction:

\displaystyle  (14.5cm)(3cm)

simplify multiplication:

\displaystyle  \boxed{ \rm {43.5 \: cm}^{2} }

<h3>Question-2:</h3>

our given shape is trapezoid

therefore recall that,

\displaystyle   A _{ \text{trapezoid}} =  \frac{a + b}{2} h

from the shape we define that

  • a = 9
  • b = 19
  • h = 8

now substitute:

\displaystyle   \rm A _{ \text{trapezoid}} =  \frac{9cm + 19cm}{2} (8cm)

reduce fraction:

\displaystyle   \rm A _{ \text{trapezoid}} =  (9cm + 19cm)(4cm)

simplify addition:

\displaystyle   \rm A _{ \text{trapezoid}} = (28cm)(4cm)

simplify multiplication:

\displaystyle   \rm A _{ \text{trapezoid}} =  \boxed{112 {cm}^{2} }

kicyunya [14]3 years ago
3 0

Answer:

43.5 cm² and 112 cm²

Step-by-step explanation:

Here the instructions aren't given what to do. So I am finding the area of the ∆s .

<u>Area </u><u>of</u><u> </u><u>first </u><u>∆</u><u> </u><u>:</u><u>-</u><u> </u>

  • A = 1/2 * b * h
  • A = 1/2 * 14.5 cm * 6cm
  • A = 3 × 14.5 cm²
  • A = 43.5 cm²

<u>Area </u><u>of</u><u> </u><u>second</u><u> </u><u>∆</u><u> </u><u>:</u><u>-</u><u> </u>

  • A = 1/2 * ( sum of || sides) * h
  • A = 1/2 * ( 9 cm + 19cm) * 8cm
  • A = 4cm * 28cm
  • A = 112 cm²
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