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kakasveta [241]
3 years ago
5

how much would $150 invested at 8% interest compounded anually be worth after 13 years? A(t)=P(1+r/n)^

Mathematics
1 answer:
PIT_PIT [208]3 years ago
3 0
\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$150\\
r=rate\to 8\%\to \frac{8}{100}\to &0.08\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &13
\end{cases}
\\\\\\
A=150\left(1+\frac{0.08}{1}\right)^{1\cdot 13}\implies A=150(1.08)^{13}\implies A\approx 407.9435589
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saveliy_v [14]
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Then rearrange the equation to get 10x on the same side as 25.

Keep in mind, once bringing to the other side, your constant and variable will switch to a negative or positive for example,
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Continuing on once rearranged, your equation will look like,
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Then we have to get rid of the 2 on 2y so you will have to divide both sides by 2.
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Dividing both sides by 2, you will get,
y = - 5x + \frac{25}{2}
The reason why we don't divide and rather keep the 25/2 (25 divded by 2) is because 25 divided by 2 will give an answer with a decimal and that we don't want a decimal in our equation so we just keep it the way it is. If you ever get a decimal, make sure you keep it in its fraction form.
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24 is the answer to the question
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