The distance? If it is asking for the distance then its square root 313.
Answer:
SEE BELOW IN BOLD.
Step-by-step explanation:
a.
h = -16t^2 + 50t
h = 20 t
When the height is the same:
-16t^2 + 50t = 20t
-16t^2 + 30t = 0
t(-16t + 30) = 0
t = 0 or -16t + 30 = 0, so:
t = 0 or -30/-16 = 1.875
So the answer is 1.88 seconds to the nearest hundredth.
b.
For the ball
h = -16t^2 + 50t
Finding the derivative and equating to zero:
dh/dt = -32t + 50 = 0
t = -50/-32 = 1.563
Maximum height after 1.56 seconds to nearest hundredth
c.
When the ball hits the ground h = 0 so
-16t^2 + 50t = 0
-16t(t - 50/16)= 0
T = 3.13 SECONDS TO THE NEAREST HUNDERDTH
Answer:
1. F
2. G
3. H
4. E
5. C
6. B
7. A
8. D
Step-by-step explanation:
1. For a horizontal line, this is zero. F. Slope
2. These lines have the same slope. G Parallel Lines
3. These lines meet at 90°. H Perpendicular Lines
4. This is where two lines meet. E. Point of Intersection
5. For the line 3 2 6 x y , this is −3. C. Y-intercept
6. The numbers 10 and 1 /10 are examples. B Reciprocals
7. This is the name for an equation of a line in the form Ax By C 0. A. Standard Form
8. For a vertical line, the value of x is constant and equal to this D. x-intercept
Answer: 5 = y
Step-by-step explanation:
Answer:
X = 11
X = 7
Step-by-step explanation:
Part 1:
The measure of an inscribed angle is half the measure of an intercepted arc. So 1/2 mCE = m∠CDE
158 ÷ 2 = 79
You need to find x so you're going to set your equation of (8x - 9) = 79
Then you're going to add 9 to both sides to get 8x = 88
Divide both sides by 8 to get x = 11
Part 2:
We know that WY is 180 because it's a semicircle. Using this and the knowledge that ∠WXY is half the measure of the intercepted arc (180), we know that our equation should be (13x - 1) = 90
add 1 to both sides and our equation is (13x = 91)
Divide both sides by 13 and...
x = 7
