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nalin [4]
3 years ago
13

Let a1, a2 and a3 be as in (a). Let a4 =   1 4 −5  . Without doing any further calculations, find all values of t for which

there will be a unique solutions to a1y1 + a2y2 + a3y3 + a4y4 = c for every vector c in R 3 . Explain your answer
Mathematics
1 answer:
Kaylis [27]3 years ago
5 0

Answer:

Hello your question is incomplete attached below is the complete question

a) attached below

b ) Vectors a1 and a2 are linearly independent  and this is because they are a scalar multiple of each other

c)  There are 3 equations and 4 unknown hence for any t value there will be a solution

Step-by-step explanation:

A) attached below

b) Vectors a1 and a2 are linearly independent  and this is because they are a scalar multiple of each other

C) there are 3 equations and 4 unknown hence for any t value there will be a solution

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icang [17]

Answer:

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General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

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  4. Multiplication
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  6. Addition
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<u>Algebra I</u>

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<u>Algebra II</u>

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Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

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Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>

  1. Substitute in points [Distance Formula]:                                                         \displaystyle d = \sqrt{(6 - 2)^2 + (7 - 1)^2}
  2. [√Radical] (Parenthesis) Subtract:                                                                   \displaystyle d = \sqrt{4^2 + 6^2}
  3. [√Radical] Evaluate exponents:                                                                       \displaystyle d = \sqrt{16 + 36}
  4. [√Radical] Add:                                                                                                 \displaystyle d = \sqrt{52}
  5. [√Radical] Simplify:                                                                                           \displaystyle d = 2\sqrt{13}
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3 years ago
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Good morning ☕️

____________________

Step-by-step explanation:

Look at the photo below for the answer.

:)

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