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2 years ago

Why do we need to know the different abbreviation of measurements and its equivalent?

Mathematics

1 answer:

valentinak56 [21]2 years ago

7 0

Answer:

See explanation.

Step-by-step explanation:

You will need to know the abbreviations of measurements because when pertaining to the real world, an you will see things as so "This fence is about 15ft tall." or "Jacobb is 72in tall." If you do not understand the abbreviations you will not understand what anyone is ever talking about when it comes to measurements. As for knowing how to convert measures to be equivalent, that is important because some measurements are bigger than others. It doesn't make since to say 12 inches, when you can just say 1 foot.

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When does a compound inequality with OR have a solution that is the entire number line? Can the solution be bounded to one side?

dalvyx [7]

Answer:

Concept: Algebraic Analysis

$\geqslant \: \: \: \: \: \: \: \: \: \: \leqslant$
Those two symbols indicate one solution
$< \: \: \: \: \: \: \: >$
Those symbols indicate a range of values
$x < 15 < x$
Indicates two bounded answers
In an inequality there is always a solution

6 0

2 years ago

The map distance from Dodgetown to Kidville is 2.75 cm. Find the actual distance from Dodgetown to Kidville.

Fantom [35]

The answer is:

55 km (a)

7 0

3 years ago

Read 2 more answers

51 more than y is greater than -240

svet-max [94.6K]

Answer:

y + 51 ≥ -240

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

mrs.beluga is driving on a snow covered road with a drag factor of 0.2. she brakes suddenly for a deer. The tires leave a yaw ma

Aneli [31]

First, we are going to find the radius of the yaw mark. To do that we are going to use the formula: $r= \frac{c^2}{8m} + \frac{m}{2}$
where
$c$ is the length of the chord
$m$ is the middle ordinate
We know from our problem that the tires leave a yaw mark with a 52 foot chord and a middle ornate of 6 feet, so $c=52$ and $m=6$ . Lets replace those values in our formula:
$r= \frac{52^2}{8(6)} + \frac{6}{2}$
$r= \frac{2704}{48} +3$
$r= \frac{169}{3} +3$
$r= \frac{178}{3}$

Next, to find the minimum speed, we are going to use the formula: $s= \sqrt{15fr}$
where
$f$ is <span>drag factor
</span> $r$ is the radius
We know form our problem that the drag factor is 0.2, so $f=0.2$ . We also know from our previous calculation that the radius is $\frac{178}{3}$ , so $r= \frac{178}{3}$ . Lets replace those values in our formula:
$s= \sqrt{(15)(0.2)( \frac{178}{3}) }$
$s= \sqrt{178}$
$s=13.34$ mph

We can conclude that Mrs. Beluga's minimum speed before she applied the brakes was 13.34 miles per hour.

8 0

3 years ago

An individual is planning a trip to a baseball game for 16 people. Of the people planning to go to the baseball game, 8 can go o

Sedaia [141]

Answer: There are 4 people who only go to the game on Saturday.

Step-by-step explanation:

Let the number of people go on Saturday be n(A).

Let the number of people go on Sunday be n(B).

Since we have given that

n(A) = 8

n(B) = 12

n(A∪B) = 16

According to rules, we get that

$n(A)+n(B)-n(A\cap B)=n(A\cup B)\\\\8+12-n(A\cap B)=16\\\\20-n(A\cap B)=16\\\\n(A\cap B)=20-16=4$

So, n(only go on Saturday) = n(only A) = n(A) - n(A∩B) = 8-4 = 4

Hence, there are 4 people who only go to the game on Saturday.

4 0

3 years ago