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finlep [7]
3 years ago
7

The correct answer(reported to the proper number of significant figures) to the following?

Mathematics
1 answer:
Pavel [41]3 years ago
5 0
<span>(12.67 + 19.2)(3.99) / (1.36 + 11.366) = 31.87(3.99) / 12.726 = 127.1613 / 12.726 = 9.992</span>
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Write the standard equation of the circle below.
s344n2d4d5 [400]

Answer:

The first answer is correct.

(x + 1)^2 + (y - 2)^2 = 1

A circle with the midpoint M(Mx, My) and the radius r can be written as

(x - Mx)^2 + (y - My)^2 = r^2


7 0
3 years ago
Kyle's car repair costs $1000. He has 2 coupons which could save him $80 off of $1000, or 15% off of $1000. EXPLAIN WHICH COUPON
never [62]
Answer:

Kyle would save more using his 15% off of $1000 coupon.

Explanation:

15 ÷ 100 • 1000 = 150

1000 - 150 = $850

$150 is the amount the 15% coupon took off.

$850 is the amount Kyle will pay.

vs.

1000 - 80 = $920
6 0
2 years ago
Help please asap :)))
iVinArrow [24]

Answer:

Step-by-step explanation:

The volume is calculated like:

V= length* hauteur* wide

V= 5* 2 3/4* 10 1/2

V= 5*\frac{11}{4} *\frac{21}{2} =\frac{5*11*21}{4*2} =\frac{1155}{8}=144.375  \\=144 \frac{3}{8} in^{3}

3 0
3 years ago
What are the relative frequencies, to the nearest hundredth, of the rows of the two-way table?
sveta [45]

Answer:       A                 B

Group 1     0.25          0.75

Group 2    0.44          0.56

Step-by-step explanation:

Since we have given that

Number of people of A in group 1 = 15

Number of people of B in group 1 = 45

Total number of people in group 1 is given by

15+45=60

Relative frequency of people of A in Group 1 is given by

\frac{15}{60}=0.25

Relative frequency of people of B in Group 1 is given by

\frac{45}{60}=0.75

Similarly, Number of people of A in group 2 = 20

Number of people of B in group 2 = 25

Total number of people in group 2 is given by

20+25=45

Relative frequency of people of A in Group 2 is given by

\frac{20}{45}=0.44

Relative frequency of people of B in Group 2 is given by

\frac{25}{45}=0.56

Hence,        A                 B

Group 1     0.25          0.75

Group 2    0.44          0.56

6 0
3 years ago
The measure of position called the midquartile of a data set is found using the formula StartFraction Upper Q 1 plus Upper Q 3 O
irinina [24]

Answer:

35.25

Step-by-step explanation:

Give the data set:

23 37 49 34 35 41 40 26 32 22 38 42

We are expected to calculate the midquartile of the given data set.

22 23 26 32 34 35 37 38 40 41 42 49

First step is to find the lower quartile which comprises of

22 23 26 32 34 35

Here the Q1 is (26+32)/2 = 58/2= 29

Second step to find the upper quartile which comprises of

37 38 40 41 42 49

Here the Q3 is (40+41) /2 = 81/2 = 41.5

Then to find the midquartile which is (Q1+Q3) /2 where Q1 is 29 and Q3 is 41.5

= (29+41.5)/2

= (70.5) /2 = 35.25

8 0
3 years ago
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